
Projectile motion is the motion of an object that moves under the influence of gravity only after being launched.
Assumptions:
Projectile motion combines:
These two motions are independent.
In the horizontal direction:
\(a_x=0\)
Therefore horizontal velocity remains constant.
\(v_x=v_{0x}\)
Horizontal position:
\(x=x_0+v_{0x}t\)
In the vertical direction:
\(a_y=-g\)
where:
\(g\approx9.8m/s^2\)
Vertical velocity:
\(v_y=v_{0y}-gt\)
Vertical position:
\(y=y_0+v_{0y}-\frac{1}{2}gt^2\)
If an object is launched with speed \(v_0\) at angle θ:
\(v_{0x}=v_0\cos\theta\)
\(v_{0y}=v_0\sin\theta\)
These are obtained by resolving the launch velocity into components.
Projectile motion produces a parabolic path.
This occurs because:
If launch and landing heights are the same:
\(T=\frac{2v_0\sin\theta}{g}\)
The projectile spends equal time rising and falling.
At the highest point:
\(v_y=0\)
Using kinematics:
\(H=\frac{{v_0}^2\sin^2\theta}{2g}\)
Range is the horizontal distance traveled.
\(R=\frac{{v_0}^2\sin(2\theta)}{g}\)
Maximum range occurs when:
\(\theta=45^\circ\)
(for equal launch and landing heights)
Velocity changes continuously because the vertical component changes.
\(\vec{v}=v_x\hat{i}+v_y\hat{j}\)
Magnitude of velocity:
\(|\vec{v}|=\sqrt{{v_x}^2+{v_y}^2}\)
This follows:
Gravity affects only vertical motion.
Even at the highest point:
Without air resistance:
Position vector:
\(\vec{r}(t)=(x_0+v_0t)\hat{i}+\left(y_0+v_0t-\frac{1}{2}gt^2\right)\hat{j}\)
Velocity vector:
\(\vec{v}(t)=v_{0x}\hat{i}+(v_{0y}-gt)\hat{j}\)
Projectile motion is two-dimensional motion under gravity.
Horizontal motion:
\(a_x=0\)
Vertical motion:
\(a_y=-g\)
Key equations:
\(v_{0x}=v_0\cos\theta\)
\(v_{0y}=v_0\sin\theta\)
\(x=v_{0x}t\)
\(y=v_{0y}t-\frac{1}{2}gt^2\)
Projectile motion combines constant horizontal velocity with vertical acceleration, producing a parabolic trajectory.
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