
Position describes where an object is located relative to a reference point (origin).
In one dimension:
$$x(t)$$
In three dimensions:
\(\vec{r}(t)=x(t)\hat{i}+y(t)\hat{j}+z(t)\hat{k}\)
Distance is the total length of the path traveled by an object.
Characteristics:
Example:
If an object moves
3 m forward, then 2 m backward
Distance:
3m+2m=5 m
Displacement is the change in position.
Δr⃗=r⃗f−r⃗i\Delta \vec{r} = \vec{r}_f – \vec{r}_iΔr=rf−ri
where:
Displacement is a vector, so it has both magnitude and direction.
Δx=xf−xi\Delta x = x_f – x_iΔx=xf−xi
Example:
xi=2 m,xf=10 mx_i = 2\,\text{m}, \quad x_f = 10\,\text{m}xi=2m,xf=10m Δx=8 m\Delta x = 8\,\text{m}Δx=8m
| Quantity | Type | Depends on |
|---|---|---|
| distance | scalar | total path |
| displacement | vector | start and end points |
Example:
Move 5 m east, then 5 m west:
Distance:
10 m10\,\text{m}10m
Displacement:
000
If an object moves from:
(xi,yi)→(xf,yf)(x_i, y_i) \rightarrow (x_f, y_f)(xi,yi)→(xf,yf)
Then:
Δr⃗=(xf−xi, yf−yi)\Delta \vec{r} = (x_f – x_i,\; y_f – y_i)Δr=(xf−xi,yf−yi)
Magnitude:
∣Δr⃗∣=(Δx)2+(Δy)2|\Delta \vec{r}| = \sqrt{(\Delta x)^2 + (\Delta y)^2}∣Δr∣=(Δx)2+(Δy)2
This follows:
These distinctions are essential because:
Position:
r⃗(t)\vec{r}(t)r(t)
Distance:
Displacement:
Δr⃗=r⃗f−r⃗i\Delta \vec{r} = \vec{r}_f – \vec{r}_iΔr=rf−ri
These concepts form the foundation of all motion analysis in kinematics.
You have not completed all required lessons and assessments.