
A pulley system uses ropes and rotating wheels to transmit forces and change the direction of motion.
In mechanics problems, pulleys are used to analyze:
In introductory mechanics, pulleys are usually assumed to be:
Under these assumptions:
If the rope is ideal:
T=constantT = \text{constant}T=constant
throughout the rope.
The tension force always pulls:
A fixed pulley changes the direction of force but not its magnitude.
Example:
Pulling downward on one side lifts an object upward on the other side.
For an object of mass mmm:
∑F=ma\sum F = ma∑F=ma
If moving vertically:
T−mg=maT – mg = maT−mg=ma
One of the most important pulley systems is the Atwood machine.
Two masses are connected by a rope over a pulley.
Assume:
m2>m1m_2 > m_1m2>m1
Then:
Both masses have the same acceleration magnitude because the rope length remains constant.
For m1m_1m1:
T−m1g=m1aT – m_1 g = m_1 aT−m1g=m1a
For m2m_2m2:
m2g−T=m2am_2 g – T = m_2 am2g−T=m2a
Adding equations eliminates tension:
m2g−m1g=(m1+m2)am_2 g – m_1 g = (m_1 + m_2)am2g−m1g=(m1+m2)a
Thus:
a=(m2−m1)gm1+m2a = \frac{(m_2 – m_1)g}{m_1 + m_2}a=m1+m2(m2−m1)g
Substitute acceleration into either equation:
T=m1(g+a)T = m_1(g+a)T=m1(g+a)
or
T=m2(g−a)T = m_2(g-a)T=m2(g−a)
Both give the same result.
In pulley systems, rope length remains constant.
This creates motion constraints:
for connected sections of rope.
Pulley systems are often combined with inclines.
Example:
Then:
For the incline object:
∑F∥=ma\sum F_{\parallel} = ma∑F∥=ma
where gravity component along slope is:
mgsinθmg\sin\thetamgsinθ
Normal force:
N=mgcosθN = mg\cos\thetaN=mgcosθ
Friction may also appear.
Pulley problems require careful free-body diagrams.
For each object:
Common forces:
Pulley systems illustrate:
They are foundational for studying:
In ideal pulley systems:
Newton’s Second Law is applied to each object separately:
∑F⃗=ma⃗\sum \vec{F} = m\vec{a}∑F=ma
For an Atwood machine:
a=(m2−m1)gm1+m2a = \frac{(m_2 – m_1)g}{m_1 + m_2}a=m1+m2(m2−m1)g
Key ideas:
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