
Work is the transfer of energy that occurs when a force acts on an object while the object undergoes a displacement.
In mechanics, work measures how effectively a force changes an object’s energy.
For a constant force acting through a displacement:
\(W=\vec{F}\cdot\delta\vec{r}\)
Using the definition of the dot product:
\(W=F\delta r\cos\theta\)
where:
The angle determines how much of the force contributes to the motion.
\(\theta=0\circ\)
\(W=F\delta r\)
Maximum positive work.
\(\theta=90\circ\)
\(W=0\)
No work is done.
\(\theta=180\circ\)
\(W=-F\delta r\)
Negative work.
Occurs when force and displacement point generally in the same direction.
Examples:
Positive work increases kinetic energy.
Occurs when force opposes displacement.
Examples:
Negative work decreases kinetic energy.
The SI unit of work is the joule (J).
\(1J=1N\cdot m\)
One joule represents one newton acting through one meter of displacement.
Only the component of force parallel to the displacement performs work.
If:
\(F_x=F\cos\theta\)
then:
\(W=F_x\delta r\)
The perpendicular component contributes no work.
In AP Physics C, forces are often not constant.
For a variable force:
\(W=\int\vec{F}\cdot d\vec{r}\)
This is the calculus definition of work.
For one-dimensional motion:
\(W=\intF(x)dx\)
The work equals the area under the force-versus-position graph.
Positive area represents positive work.
Negative area represents negative work.
A person lifts a mass vertically upward.
Applied force and displacement are in the same direction.
\(W=Fd\)
Positive work is done by the person.
Friction acts opposite the displacement.
\(W_f=-fd\)
Friction removes mechanical energy from the system.
The upward force exerted by your arms is perpendicular to the horizontal displacement.
\(W=0\)
No work is done by the upward support force.
Work is important because it changes energy.
The Work–Energy Theorem states:
\(W_{net}=\delta K\)
where:
This theorem forms the foundation of energy methods in mechanics.
Work measures energy transfer caused by a force acting through a displacement.
For a constant force:
\(W=Fd\cos\theta\)
The work expression is based on the dot product:
\(\vec{F}\cdot\delta\vec{r}\)
Key ideas:
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