
The kinematics of Simple Harmonic Motion (SHM) describes how an oscillating object’s position, velocity, and acceleration change with time.
Unlike constant-acceleration motion, SHM involves continuously changing velocity and acceleration.
Examples of SHM include:
The motion is periodic and repeats itself after a fixed interval of time.
Simple Harmonic Motion is motion in which the acceleration is directly proportional to displacement and opposite in direction.
a=−ω2xa=-\omega^2xa=−ω2x
where:
The negative sign indicates that the acceleration always points toward the equilibrium position.
During one complete cycle:
This repeating motion defines an oscillation.
Amplitude is the maximum displacement from equilibrium.
Symbol:
AAA
Units:
mmm
The object oscillates between:
+A+A+A
and
−A-A−A
The period is the time required for one complete oscillation.
Symbol:
TTT
Units:
sss
After one period:
x(t+T)=x(t)x(t+T)=x(t)x(t+T)=x(t)
The motion repeats exactly.
Frequency is the number of oscillations per second.
f=1Tf = \frac{1}{T}f=T1
Units:
HzHzHz
Angular frequency measures how rapidly the oscillation occurs.
ω=2πf\omega = 2\pi fω=2πf
or
ω=2πT\omega = \frac{2\pi}{T}ω=T2π
Larger values of ω\omegaω correspond to faster oscillations.
The displacement in SHM is described by a sinusoidal function.
x(t)=Acos(ωt+ϕ)x(t) = A\cos(\omega t+\phi)x(t)=Acos(ωt+ϕ)
where:
The motion can also be written as:
x(t)=Asin(ωt+ϕ)x(t) = A\sin(\omega t+\phi)x(t)=Asin(ωt+ϕ)
Both equations describe SHM.
The position-versus-time graph is a sine or cosine curve.
Characteristics:
The graph repeats every period TTT.
Velocity is the derivative of position.
Starting with:
x(t)=Acos(ωt+ϕ)x(t) = A\cos(\omega t+\phi)x(t)=Acos(ωt+ϕ)
Differentiating:
v(t)=−Aωsin(ωt+ϕ)v(t) = -A\omega \sin(\omega t+\phi)v(t)=−Aωsin(ωt+ϕ)
The maximum speed occurs at equilibrium.
vmax=Aωv_{\max} = A\omegavmax=Aω
x=0x=0x=0
Velocity reaches its greatest magnitude.
The velocity graph is also sinusoidal.
It is shifted by one-quarter cycle relative to the position graph.
Position and velocity are always out of phase by:
90∘90^\circ90∘
or
π2\frac{\pi}{2}2π
radians.
Acceleration is the derivative of velocity.
Starting with:
v(t)=−Aωsin(ωt+ϕ)v(t) = -A\omega \sin(\omega t+\phi)v(t)=−Aωsin(ωt+ϕ)
Differentiating:
a(t)=−Aω2cos(ωt+ϕ)a(t) = -A\omega^2 \cos(\omega t+\phi)a(t)=−Aω2cos(ωt+ϕ)
Since:
x(t)=Acos(ωt+ϕ)x(t) = A\cos(\omega t+\phi)x(t)=Acos(ωt+ϕ)
we obtain:
a=−ω2xa=-\omega^2xa=−ω2x
Acceleration is greatest at the turning points.
amax=ω2Aa_{\max} = \omega^2Aamax=ω2A
x=±Ax=\pm Ax=±A
Velocity is zero.
Acceleration is maximum.
The three kinematic variables are not maximized at the same time.
Maximum at:
x=±Ax=\pm Ax=±A
Maximum at:
x=0x=0x=0
Maximum at:
x=±Ax=\pm Ax=±A
| Quantity | At Equilibrium | At Turning Point |
|---|---|---|
| Position | 0 | ±A |
| Velocity | Maximum | 0 |
| Acceleration | 0 | Maximum |
| Force | 0 | Maximum |
A useful equation relates velocity and position directly.
v2=ω2(A2−x2)v^2 = \omega^2(A^2-x^2)v2=ω2(A2−x2)
This equation eliminates time from the analysis.
At equilibrium:
x=0x=0x=0 v=vmax=Aωv=v_{\max}=A\omegav=vmax=Aω
At a turning point:
x=Ax=Ax=A v=0v=0v=0
A block oscillates with:
A=0.20 mA=0.20\,mA=0.20m
and
ω=5 rad/s\omega=5\,rad/sω=5rad/s
Find the maximum speed.
Using:
vmax=Aωv_{\max} = A\omegavmax=Aω
Substitute values:
vmax=(0.20)(5)v_{\max} = (0.20)(5)vmax=(0.20)(5) vmax=1.0 m/sv_{\max} = 1.0\,m/svmax=1.0m/s
Using the previous oscillator, find the maximum acceleration.
Using:
amax=ω2Aa_{\max} = \omega^2Aamax=ω2A
Substitute values:
amax=(5)2(0.20)a_{\max} = (5)^2(0.20)amax=(5)2(0.20) amax=25(0.20)a_{\max} = 25(0.20)amax=25(0.20) amax=5.0 m/s2a_{\max} = 5.0\,m/s^2amax=5.0m/s2
Cosine or sine wave.
Shifted by one-quarter period.
Opposite in sign to position.
Because:
a=−ω2xa=-\omega^2xa=−ω2x
the acceleration graph is an inverted version of the position graph.
Assuming acceleration is greatest at equilibrium.
Actually:
a=0a=0a=0
at equilibrium.
Assuming velocity is greatest at maximum displacement.
Velocity is zero at the turning points.
Forgetting the negative sign in:
a=−ω2xa=-\omega^2xa=−ω2x
The negative sign indicates the restoring nature of SHM.
Velocity is the derivative of position.
Acceleration is the derivative of velocity.
SHM results from restoring forces.
The kinematic variables are directly related to kinetic and potential energy.
The same kinematic principles apply to springs, pendulums, and many other oscillating systems.
Position:
x(t)=Acos(ωt+ϕ)x(t) = A\cos(\omega t+\phi)x(t)=Acos(ωt+ϕ)
Velocity:
v(t)=−Aωsin(ωt+ϕ)v(t) = -A\omega \sin(\omega t+\phi)v(t)=−Aωsin(ωt+ϕ)
Acceleration:
a(t)=−ω2xa(t) = -\omega^2xa(t)=−ω2x
Angular frequency:
ω=2πT\omega = \frac{2\pi}{T}ω=T2π
Maximum velocity:
vmax=Aωv_{\max} = A\omegavmax=Aω
Maximum acceleration:
amax=ω2Aa_{\max} = \omega^2Aamax=ω2A
Velocity-position relation:
v2=ω2(A2−x2)v^2 = \omega^2(A^2-x^2)v2=ω2(A2−x2)
Key ideas:
The kinematics of Simple Harmonic Motion provides the mathematical description of oscillations and serves as the foundation for analyzing springs, pendulums, waves, and many advanced topics in AP Physics C Mechanics.
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