
By the end of this lesson, students should be able to:
Define magnetic flux.
State and apply Faraday’s Law of Induction.
Calculate induced EMF from changing magnetic flux.
Understand the significance of the negative sign in Faraday’s Law.
Analyze situations involving changing magnetic fields, changing areas, and changing orientations.
Solve AP Physics C problems involving electromagnetic induction.
In 1831, Michael Faraday discovered that changing magnetic fields can produce electric currents.
This discovery established a deep connection between electricity and magnetism and became one of the foundations of modern electrical technology.
Today, Faraday’s Law explains the operation of:
Electric generators
Transformers
Induction cooktops
Wireless charging systems
Power plants
Electromagnetic induction is the production of an electromotive force (EMF) caused by a changing magnetic environment.
A current can be induced by:
Changing magnetic field strength
Changing loop area
Changing loop orientation
Moving conductors through magnetic fields
The common feature is a change in magnetic flux.
Magnetic flux measures the amount of magnetic field passing through a surface.
It is defined as:
$$
\Phi_B=\vec{B}\cdot\vec{A}
$$
The magnitude is:
$$
\Phi_B=BA\cos\theta
$$
where:
(B) = magnetic field strength
(A) = area of the surface
(\theta) = angle between (\vec{B}) and the area vector
The SI unit of magnetic flux is:
$$
T\cdot m^2
$$
which is also called a:
$$
\text{weber (Wb)}
$$
The area vector is perpendicular to the surface.
For a flat loop:
The vector points normal to the plane.
Either normal direction may be chosen consistently.
The angle in the flux equation is measured relative to the area vector.
When the magnetic field is parallel to the area vector:
$$
\theta=0^\circ
$$
then:
$$
\Phi_B=BA
$$
Flux is maximum.
When:
$$
\theta=90^\circ
$$
then:
$$
\Phi_B=0
$$
No magnetic field passes through the surface.
Faraday’s Law states:
The induced EMF equals the negative rate of change of magnetic flux.
Mathematically:
$$
\boxed{\mathcal{E}-\frac{d\Phi_B}{dt}}
$$
For a coil containing (N) turns:
$$
\boxed{\mathcal{E}-N\frac{d\Phi_B}{dt}}
$$
Each loop contributes equally to the total induced EMF.
The negative sign represents:
$$
\text{Lenz’s Law}
$$
Lenz’s Law states:
The induced current always opposes the change in magnetic flux that created it.
Nature resists changes in magnetic flux.
If flux increases:
Induced current produces a magnetic field that opposes the increase.
If flux decreases:
Induced current produces a magnetic field that opposes the decrease.
Since:
$$
\Phi_B=BA\cos\theta
$$
changing (B) changes the flux.
Examples:
Moving a magnet closer to a loop
Increasing current in an electromagnet
Changing the area enclosed by a loop changes flux.
Examples:
Sliding conducting rods
Expanding loops
Rotating a loop changes:
$$
\theta
$$
and therefore changes flux.
This principle is used in electric generators.
Consider a rod moving through a magnetic field.
The area changes with time.
Flux becomes:
$$
\Phi_B=BABLx
$$
Differentiating:
$$
\frac{d\Phi_B}{dt}=BL\frac{dx}{dt}
$$
Since:
$$
\frac{dx}{dt}=v
$$
we obtain:
$$
\mathcal{E}=BLv
$$
Thus motional EMF is a special case of Faraday’s Law.
If the loop has resistance:
$$
R
$$
then the induced current is:
$$
I=\frac{\mathcal{E}}{R}
$$
Combining with Faraday’s Law:
$$
I=\frac{1}{R}\left|\frac{d\Phi_B}{dt}\right|
$$
A circular loop has area:
$$
A=0.20m^2
$$
A magnetic field increases from:
$$
0.50T
$$
to
$$
1.50T
$$
in:
$$
0.10s
$$
Find the induced EMF.
Calculate the change in flux:
$$
\Delta\Phi_B=A\Delta B
$$
$$
\Delta\Phi_B=(0.20)(1.0)
$$
$$
\Delta\Phi_B=0.20Wb
$$
Apply Faraday’s Law:
$$
\mathcal{E}=\frac{\Delta\Phi_B}{\Delta t}
$$
$$
\mathcal{E}=\frac{0.20}{0.10}
$$
$$
\mathcal{E}=2.0V
$$
$$
\mathcal{E}=2.0V
$$
A loop of area:
$$
0.10m^2
$$
rotates from:
$$
0^\circ
$$
to
$$
90^\circ
$$
in a magnetic field:
$$
B=0.80T
$$
Find the change in flux.
Initial flux:
$$
\Phi_i=BA\cos0^\circ
$$
$$
\Phi_i=(0.80)(0.10)
$$
$$
\Phi_i=0.080Wb
$$
Final flux:
$$
\Phi_f=BA\cos90^\circ0
$$
Thus:
$$
\Delta\Phi_B=0.080Wb
$$
$$
\Delta\Phi_B=0.080Wb
$$
A coil contains:
$$
N=200
$$
turns.
The magnetic flux changes at a rate:
$$
\frac{d\Phi_B}{dt}=0.015Wb/s
$$
Find the induced EMF.
Use:
$$
\mathcal{E}=N\frac{d\Phi_B}{dt}
$$
Substitute:
$$
\mathcal{E}=(200)(0.015)
$$
$$
\mathcal{E}=3.0V
$$
$$
\mathcal{E}=3.0V
$$
A rotating loop in a magnetic field continuously changes:
$$
\theta
$$
and therefore changes magnetic flux.
According to Faraday’s Law:
An alternating EMF is produced.
This is the operating principle behind electric power generation.
Faraday’s Law does not create energy.
An external source must perform work to change the magnetic flux.
Examples:
Rotating a generator
Moving a conductor
Operating a turbine
Mechanical energy becomes electrical energy.
Using magnetic field instead of magnetic flux.
Remember:
Faraday’s Law depends on:
$$
\Phi_B
$$
not simply (B).
Ignoring the angle term.
The correct flux expression is:
$$
\Phi_B=BA\cos\theta
$$
Forgetting the number of turns.
For coils:
$$
\mathcal{E}=-N\frac{d\Phi_B}{dt}
$$
The factor (N) is crucial.
Identify what causes the flux change:
Changing (B)?
Changing (A)?
Changing (\theta)?
Calculate magnetic flux:
$$
\Phi_B=BA\cos\theta
$$
Find the rate of change:
$$
\frac{d\Phi_B}{dt}
$$
Apply Faraday’s Law:
$$
\mathcal{E}=-N\frac{d\Phi_B}{dt}
$$
Magnetic flux is:
$$
\Phi_B=BA\cos\theta
$$
The SI unit of flux is:
$$
1Wb=1T\cdot m^2
$$
Faraday’s Law states:
$$
\boxed{\mathcal{E}-\frac{d\Phi_B}{dt}}
$$
For multiple loops:
$$
\boxed{\mathcal{E}-N\frac{d\Phi_B}{dt}}
$$
Flux changes can result from:
Changing magnetic field strength
Changing area
Changing orientation
The negative sign represents Lenz’s Law.
Motional EMF:
$$
\mathcal{E}=BLv
$$
is a special case of Faraday’s Law.
Faraday’s Law is the fundamental principle behind electric generators, transformers, and electromagnetic induction.
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