Alternating Series
What Is an Alternating Series?
An alternating series is a series whose terms alternate in sign:
$$a_{1}-a_{2}+a_{3}-a_{4}+\ldots$$
or more generally:
where:
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$$a_{n} > 0$$ for all n
-
Signs switch
Example
$$1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\ldots$$
This is the famous alternating harmonic series.
⭐ 2. Alternating Series Test (Leibniz Test)
This test determines whether an alternating series converges.
✔ The Alternating Series Test:
An alternating series
∑(−1)n−1an\sum (-1)^{n-1} a_n
converges if:
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an>0a_n > 0
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an+1≤ana_{n+1} \le a_n (the sequence is decreasing)
-
limn→∞an=0\lim_{n \to \infty} a_n = 0
If all three conditions hold → the series converges.
3. Conditional vs. Absolute Convergence
Absolute Convergence
If
∑∣an∣\sum |a_n|
converges, then the series converges absolutely.
Conditional Convergence
If
-
∑an\sum a_n converges, but
-
∑∣an∣\sum |a_n| diverges
then the series converges conditionally.
Example: Alternating Harmonic Series
∑(−1)n−11n\sum (-1)^{n-1} \frac{1}{n}
-
Converges (by Alternating Series Test)
-
But:
∑1n=diverges\sum \frac{1}{n} = \text{diverges}
So it is conditionally convergent.
📏 4. Alternating Series Error Bound
For a convergent alternating series:
S=a1−a2+a3−⋯S = a_1 – a_2 + a_3 – \cdots
The error when approximating with nn terms:
∣S−Sn∣≤an+1|S – S_n| \le a_{n+1}
Meaning:
The next unused term gives the maximum possible error.
Example
1−12+131 – \frac{1}{2} + \frac{1}{3}
Error ≤ next term:
≤14\le \frac{1}{4}
🧠 5. Worked Examples
Example 1: Test for convergence
∑n=1∞(−1)n+11n2\sum_{n=1}^{\infty} (-1)^{n+1}\frac{1}{n^2}
Check AST:
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Positive? → 1/n2>01/n^2 > 0 ✔
-
Decreasing? → Yes ✔
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Limit zero? → lim1/n2=0\lim 1/n^2 = 0 ✔
Conclusion: Converges.
Absolute convergence?
∑1n2 converges\sum \frac{1}{n^2} \text{ converges}
So, the alternating series converges absolutely.
Example 2: Conditional or absolute?
∑n=1∞(−1)n−11n\sum_{n=1}^{\infty} (-1)^{n-1} \frac{1}{n}
-
AST shows: converges
-
Check absolute:
∑1n=diverges\sum \frac{1}{n} = \text{diverges}
→ Conditionally convergent
Example 3: Error Bound
Approximate:
ln(2)=1−12+13−14+⋯\ln(2) = 1 – \frac{1}{2} + \frac{1}{3} – \frac{1}{4} + \cdots
Using first 5 terms:
Error ≤ 6th term:
≤16\le \frac{1}{6}