
Trigonometric functions are fundamental in calculus because they appear frequently in physics, engineering, and geometry. Understanding how to differentiate them allows us to analyze oscillations, wave motion, and circular motion.
In this lecture, you will learn how to find derivatives of the six basic trigonometric functions.
Let’s go over each one carefully.
Derivative of Sine
$$\frac{d}{dx}[sin(x)]=cos(x)$$
$$\frac{d}{dx}[sin(u)]=cos(u)\frac{du}{dx}$$
$$\lim\limits_{h \to 0}\frac{sin(x+h)-sin(x)}{h}$$
$$=\lim\limits_{h \to 0}\frac{sin(x)cos(h)+sin(h)cos(x)-sin(x)}{h}$$
$$=\lim\limits_{h \to 0}\frac{sin(x)(cos(h)-1)+sin(h)cos(x)}{h}$$
$$=\lim\limits_{h \to 0}\frac{sin(x)(cos(h)-1)}{h}+\lim\limits_{h \to 0}\frac{sin(h)cos(x)}{h}$$
$$=sin(x)\cdot{0}+1\cdot cos(x)$$
$$=cos(x)$$
example)
$$g(x)=sin(2x)$$
$$g^\prime(x)=cos(2x)\cdot(2x)^\prime$$
$$=cos(2x)\cdot2=2cos(2x)$$
$$h(x)=sin(x^3)$$
$$h^\prime(x)=cos(x^3)\cdot(x^3)^\prime$$
$$=cos(x^3)\cdot(3x^2)=3x^2cos(x^3)$$
$$\frac{d}{dx}[cos(x)]=-sin(x)$$
$$\frac{d}{dx}[cos(u)]=-sin(u)\frac{du}{dx}$$
$$\lim\limits_{h \to 0}\frac{cos(x+h)-cos(x)}{h}$$
$$=\lim\limits_{h \to 0}\frac{cos(x)cos(h)-sin(h)sin(x)-cos(x)}{h}$$
$$=\lim\limits_{h \to 0}\frac{cos(x)(cos(h)-1)-sin(h)sin(x)}{h}$$
$$=\lim\limits_{h \to 0}\frac{cos(x)(cos(h)-1)}{h}-\lim\limits_{h \to 0}\frac{sin(h)sin(x)}{h}$$
$$=cos(x)\cdot{0}-1\cdot sin(x)$$
$$=-sin(x)$$
example)
$$g(x)=2xcos(x^2)$$
$$g^\prime(x)=(2x)^\prime\cdot cos(x^2)+2x\cdot(cos(x^2))^\prime$$
$$=2\cdot cos(x^2)+2x\cdot -sin(x^2)\cdot(x^2)^\prime$$
$$=2cos(x^2)+2x\cdot -sin(x^2)\cdot(2x)$$
$$=2cos(x^2)-4x^2sin(x^2)$$
$$\frac{d}{dx}[tan(x)]=sec^2(x)$$
$$\frac{d}{dx}[tan(u)]=sec^2(u)\frac{du}{dx}$$
$$f(x)=tan(x)=\frac{sin(x)}{cos(x)}$$
$$f^\prime(x)=\frac{(sin(x))^\prime\cdot cos(x)-sin(x)(cos(x))^\prime}{(cos(x))^2}$$
$$=\frac{cos(x)\cdot cos(x)-sin(x)\cdot(-sin(x))}{cos^2(x)}$$
$$=\frac{cos^2(x)+sin^2(x)}{cos^2(x)}$$
$$=\frac{1}{cos^2(x)}$$
$$=sec^2(x)$$
example)
$$g(x)=\frac{tan(x)}{sin(x)}$$
$$g^\prime=\frac{(tan(x))^\prime\cdot sin(x)-tan(x)\cdot(sin(x))^\prime}{(sin(x))^2}$$
$$=\frac{sec^2(x)sin(x)-tan(x)cos(x)}{cos^2(x)}$$
$$\frac{d}{dx}[cot(x)]=-csc^2(x)$$
$$\frac{d}{dx}[cot(u)]=-csc^2(u)\frac{du}{dx}$$
$$f(x)=cot(x)=\frac{cos(x)}{sin(x)}$$
$$f^\prime(x)=\frac{(cos(x))^\prime\cdot sin(x)-cos(x)(sin(x))^\prime}{(sin(x))^2}$$
$$=\frac{-sin(x)\cdot sin(x)-cos(x)\cdot cos(x)}{sin^2(x)}=\frac{-(sin^2(x)+cos^2(x))}{sin^2(x)}$$
$$=\frac{-1}{sin^2(x)}=-csc^2(x)$$
example)
$$g(x)=cot(3x^2)$$
$$g^\prime(x)=-csc(3x^2)cot(3x^2)\cdot(3x^2)^\prime$$
$$=-6x csc(3x^2)cot(3x^2)$$
$$\frac{d}{dx}[sec(x)]=sec(x)tan(x)$$
$$\frac{d}{dx}[sec(u)]=sec(u)tan(u)\frac{du}{dx}$$
$$f(x)=sex(x)=\frac{1}{cos(x)}$$
$$f^\prime(x)=\frac{1^\prime\cdot cos(x)-1\cdot(cos(x))^\prime}{(cos(x))^2}$$
$$=\frac{sin(x)}{cos^2(x)}=\frac{1}{cos(x)}\cdot\frac{sin(x)}{cos(x)}$$
$$=sec(x)tan(x)$$
example)
$$g(x)=sec(4x)$$
$$g^\prime(x)=sec(4x)tan(4x)\cdot(4x)^\prime$$
$$=4sec(4x)tan(4x)$$
$$\frac{d}{dx}[csc(x)]=-csc(x)cot(x)$$
$$\frac{d}{dx}[csc(u)]=-csc(u)cot(u)\frac{du}{dx}$$
$$f(x)=csc(x)=\frac{1}{sin(x)}$$
$$f^\prime(x)=\frac{1^\prime\cdot(sin(x))-1\cdot(sin(x))^\prime}{(sin(x))^2}$$
$$=\frac{-cos(x)}{sin^2(x)}=\frac{1}{sin(x)}\cdot\frac{-cos(x)}{sin(x)}$$
$$=-csc(x)cot(x)$$
example)
$$g(x)=csc(x^2+4)$$
$$g^\prime(x)=-csc(x^2+4)cot(x^2+4)\cdot(x^2+4)^\prime$$
$$=-2xcsc(x^2+4)cot(x^2+4)$$
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