
An alternating series is a series whose terms alternate in sign:
$$a_{1}-a_{2}+a_{3}-a_{4}+\ldots$$
or more generally:
$$\sum^{\infty}_{n=1}(-1)^{n-1}a_{n} or \sum^{\infty}_{n=1}(-1)^{n}a_{n}$$
where:
$$a_{n} > 0$$ for all n
Signs switch
$$1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\ldots$$
This is the famous alternating harmonic series.
This test determines whether an alternating series converges.
An alternating series
∑(−1)n−1an\sum (-1)^{n-1} a_n∑(−1)n−1an
converges if:
an>0a_n > 0an>0
an+1≤ana_{n+1} \le a_nan+1≤an (the sequence is decreasing)
limn→∞an=0\lim_{n \to \infty} a_n = 0limn→∞an=0
If all three conditions hold → the series converges.
If
∑∣an∣\sum |a_n|∑∣an∣
converges, then the series converges absolutely.
If
∑an\sum a_n∑an converges, but
∑∣an∣\sum |a_n|∑∣an∣ diverges
then the series converges conditionally.
∑(−1)n−11n\sum (-1)^{n-1} \frac{1}{n}∑(−1)n−1n1
Converges (by Alternating Series Test)
But:
∑1n=diverges\sum \frac{1}{n} = \text{diverges}∑n1=diverges
So it is conditionally convergent.
For a convergent alternating series:
S=a1−a2+a3−⋯S = a_1 – a_2 + a_3 – \cdotsS=a1−a2+a3−⋯
The error when approximating with nnn terms:
∣S−Sn∣≤an+1|S – S_n| \le a_{n+1}∣S−Sn∣≤an+1
The next unused term gives the maximum possible error.
1−12+131 – \frac{1}{2} + \frac{1}{3}1−21+31
Error ≤ next term:
≤14\le \frac{1}{4}≤41
∑n=1∞(−1)n+11n2\sum_{n=1}^{\infty} (-1)^{n+1}\frac{1}{n^2}n=1∑∞(−1)n+1n21
Check AST:
Positive? → 1/n2>01/n^2 > 01/n2>0 ✔
Decreasing? → Yes ✔
Limit zero? → lim1/n2=0\lim 1/n^2 = 0lim1/n2=0 ✔
Conclusion: Converges.
Absolute convergence?
∑1n2 converges\sum \frac{1}{n^2} \text{ converges}∑n21 converges
So, the alternating series converges absolutely.
∑n=1∞(−1)n−11n\sum_{n=1}^{\infty} (-1)^{n-1} \frac{1}{n}n=1∑∞(−1)n−1n1
AST shows: converges
Check absolute:
∑1n=diverges\sum \frac{1}{n} = \text{diverges}∑n1=diverges
→ Conditionally convergent
Approximate:
ln(2)=1−12+13−14+⋯\ln(2) = 1 – \frac{1}{2} + \frac{1}{3} – \frac{1}{4} + \cdotsln(2)=1−21+31−41+⋯
Using first 5 terms:
Error ≤ 6th term:
≤16\le \frac{1}{6}≤61
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