
Hello, class! Today, we’re tackling a concept that is incredibly intuitive yet mathematically precise: continuity. We’ll answer the question: “Can I draw the graph of this function without lifting my pencil?” More importantly, we’ll learn why this property matters so much in calculus.
Think about drawing a function.
Can you draw it in one smooth, unbroken stroke? If YES, it’s continuous.
Do you have to lift your pencil to jump to another part? If YES, it has a discontinuity.
Formal Definition:
A function f(x) is continuous at a point x=a if and only if the following three conditions:
f(a) exists. (The function is defined at x=a. There is a point to go to.)
$$\lim_{x\to a}f(x)$$ exists. (The function approaches a single, finite value as x gets close to aa.)
$$\lim_{x\to a}f(x) = f(a)$$. (The value the function is approaching is the same as the value it actually takes.)
If a function is continuous at every point in an interval, then the function is continuous on that entire interval.
Let’s see what happens when each condition fails. This is how we classify different types of discontinuities.
Function: $$f(x)=\frac{x^{2}-1}{x-1}
Point of Interest: x=1
The Autopsy:
✅ Does f(1) exist? No! Plugging in x=1 gives $$\frac{0}{0}$$, which is undefined. The point (1, 2) is missing—there’s a hole in the graph.
Since the first condition fails, the function is automatically discontinuous at x=1. Let’s check the others for curiosity:
2. ✅ $$\lim_{x\to1}f(x)$$ exists. If we simplify the function, we get $$f(x)=x+1$$for$$x\neq1$$ the limit is 2.
3. ❌ Does the limit equal the function value? There is no function value, so this also fails.
Verdict: Discontinuous at x=1. This is called a Removable Discontinuity because we could “fix” the discontinuity by simply defining f(1)=2. The limit exists, but the function value is missing or wrong.
Function: A piecewise function like:
$$g(x)= x+1 (x<2) | x-1 (x\geq2)$$
Point of Interest: x=2
The Autopsy:
✅ Does g(2) exist? Yes! g(2)=2−1=1. There is a point at (2, 1).
❌ Does $$\lim_{x\to2}$$? No!
Left-hand limit: $$\lim_{x\to2^{-}}g(x)=3$$
Right-hand limit: $$\lim_{x\to2^{+}}g(x)=1$$
The left and right limits disagree, so the overall limit Does Not Exist (DNE).
Verdict: Discontinuous at x=2. This is called a Jump Discontinuity. The function “jumps” from one value to another. This is a Non-Removable Discontinuity; you can’t fix it by redefining a single point.
Function: $$h(x)=\frac{1}{x}$$
Point of Interest: x=0
The Autopsy:
❌ Does h(0) exist? No! Division by zero is undefined.
❌ Does $$\lim_{x\to0}$$ h(x) exist? No! As x approaches 0 from the right, the function goes to $$+\infty$$. As x approaches 0 from the left, it goes to $$-\infty$$. It does not approach a finite number.
Verdict: Discontinuous at x=0. This is called an Infinite Discontinuity. The function values become arbitrarily large (positive or negative) near the point. This is also Non-Removable.
Continuity isn’t just a nice geometric property. It’s the key that unlocks many concepts in calculus.
The Intermediate Value Theorem (IVT):
If a function f is continuous on the closed interval [a,b], then it takes on every value between f(a) and f(b).
Real-World Application: If you measure 60°F at 6 AM and 80°F at noon, you know for a fact that the temperature must have been exactly 75°F at some point in between. This seems obvious, but it only holds true if temperature is a continuous function—which it is!
Differentiability Implies Continuity:
This is a huge one. If a function is differentiable at a point (meaning it has a derivative there), then it must be continuous at that point.
The Converse is FALSE: A function can be continuous but not differentiable. The classic example is f(x)=∣x∣ at x=0. It’s continuous (you can draw it without lifting your pencil), but it has a sharp corner, so it has no defined slope (derivative) there.
Easier Limit Evaluation:
If you know a function is continuous at x=a, then finding $$\lim_{x\to a}f(x)$$ is trivial: you just plug in a! This is why we love continuous functions; they behave predictably.
Let’s create a quick diagnostic flowchart for continuity at a point x=a:
Does f(a) exist?
No → Discontinuous. (Hole or Asymptote)
Yes → Proceed.
Does $$\lim_{x\to a}f(x)$$ exist?
No → Discontinuous. (Jump)
Yes → Proceed.
Does $$\lim_{x\to a}f(x)=f(a)$$?
No → Discontinuous. (Removable Hole)
Yes → Continuous!
Classification of Discontinuities:
Removable Discontinuity (Hole): The limit exists, but the function is not defined there (or is defined to be the wrong value).
Jump Discontinuity: The left and right-hand limits both exist but are not equal.
Infinite Discontinuity (Vertical Asymptote): The function values become unbounded near the point.
You have not completed all required lessons and assessments.