Error Bounds (Taylor Polynomial Remainder)
When we approximate a function using a Taylor polynomial, we want to know:
“How accurate is our approximation?”
To answer this, we use the Taylor Remainder (Error Bound).
What Is Error Bound?
When a function is approximated by its n-degree Taylor polynomial $$P_{n}(x)$$:
$$f(x)=P_{n}(x)+R_{n}(x)$$
Where:
-
$$P_{n}(x)$$ = Taylor polynomial of degree nn
-
$$R_{n}(x)$$ = remainder (error term)
The goal is to find an upper bound for $$|R_{n}(x)|$$.
Lagrange Error Bound Formula
The most important error bound formula for AP BC:
For some number c between x and the center a.
actually use on AP exam:
Find a maximum value of $$|f^{(n+1)}(c)|$$ on the interval between xx and aa.
Call this maximum value M.
Then:
$$|R_{n}(x)|\leq\frac{M}{(n+1)!}|x-a|^{n+1}$$
This is the Lagrange Error Bound.
Error Bound Process
Step 1. Identify the function and Taylor degree
Given function f(x).
Taylor polynomial centered at .
You are approximating at .
Step 2. Find -th derivative of the function
If you’re using $$P_{3}$$, compute the 4th derivative.
Step 3. Find a bound M for $$|f^{(n+1)}(c)|$$
Find the maximum value of $$|f^{(n+1)}(c)|$$ on interval between interval: x and a
Step 4. Use formula
$$|R_{n}(x)|\leq\frac{M}{(n+1)!}|x-a|^{n+1}$$
Example 1 (Classic BC Exam)
Approximate $$e^{0.2}$$ using the 2nd-degree Maclaurin polynomial.
Then find an error bound.
Step 1: Taylor polynomial degree 2
Maclaurin series for $$e^{x}$$:
Approximation:
$$e^{0.2}=1+0.2+\frac{(0.2)^{2}}{2}=1.22$$
Step 2: Use Lagrange error bound
The th derivative is $$f^{(3)}(x)=e^{x}$$.
Over the interval between 0 and 0.2:
Maximum of $$e^{x}=e^{0.2}$$.
Approximate maximum:
$$e^{0.2}<e^{0.3}<1.35$$
Thus choose
M=$$e^{0.2}\approx1.22$$
Step 3: Apply formula
Here, n=2 , a=0 , x=0.2:
$$|R_{2}(0.2)|$\leq\frac{M}{3!}|(0.2)^{3}|^{3}$$
$$=\frac{1.22}{6}(0.008)=0.00163$$
Final Answer:
$$e^{0.2}$\approx1.22$ with error < 0.00163
Example 2 (Sine Function)
Approximate $$\sin(0.3)$$ using the 3rd-degree Maclaurin polynomial and find an error bound.
Step 1: Maclaurin polynomial $$P_{3}$$
Plug in:
$$\sin(0.3)\approx0.3-\frac{(0.3)^{3}}{6}=0.3-0.0045=0.2955$$
Step 2: Find a bound for the error
For sine, the 4th derivative is:
$$f^{(4)}(x)=\sin(x)$$
But absolute value of sine is bounded:
$$|\sin(x)|\leq1$$
Thus:
M=1
Step 3: Apply error formula
$$|R_{3}(0.3)|\leq\frac{1}{4!}(0.3)^{4}$$
Final Answer:
$$\sin(0.3)\approx0.2955$$ with error < 0.00034
When Do You Use Error Bounds in BC?
You use error bounds for:
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Taylor polynomial approximations
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Alternating series error estimates
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Proving accuracy of approximations
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FRQs requiring inequality justification