The Concept of an Inverse Function
Core Idea: An inverse function reverses what the original function does.
If $$f$$ takes to , then $$f^{-1}$$ takes y back to .
Formal Definition:
Functions f and g are inverses if:
$$f(g(x))=x$$ for all x in domain of g
$$g(f(x))=x$$ for all x in domain of f
Notation: $$f^{-1}(x)$$ (read “f inverse”)
⚠️ Warning: $$f^{-1}(x)\neq\frac{1}{f(x)}$$ (that’s the reciprocal!)
The Horizontal Line Test
A function has an inverse function (is invertible) if and only if it is one-to-one (1-1).
One-to-one: Each y-value corresponds to exactly ONE x-value.
Graphical Test: If EVERY horizontal line intersects the graph at most once, the function is 1-1 and has an inverse function.
Examples:
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$$f(x)=x^2$$ fails (horizontal line at y=4 hits at x=2 and x=-2)
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$$f(x)=x^3$$ passes (any horizontal line hits exactly once)
Finding Inverses Algebraically
Step-by-Step Process:
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Replace f(x) with
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Swap x and y (this is the inverse relationship)
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Solve for y
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Replace y with $$f^{-1}(x)$$
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Verify by checking $$f(f^{-1}(x))=x$$ and $$f^{-1}(f(x))=x$$
Example : Find inverse of $$f(x)=2x+3$$
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y=2x+3
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Swap: x=2y+3
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Solve: x−3=2y ⇒ $$y=\frac{x-3}{2}$$
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Check: $$f(f^{-1}(x))=2\left(\frac{x-3}{2}\right)+3=x$$
Domain and Range of Inverses
Key Relationship:
Domain of $$f^{-1}$$ = Range of f
Range of $$f^{-1}$$ = Domain of f
Example : $$f(x)=\sqrt{x}$$ has domain [0,∞), range [0,∞)
Its inverse $$f^{-1}(x)=x^2$$ (with restricted domain!) has domain [0,∞), range [0,∞)
Wait—this seems symmetric. Actually, $$f^{-1}(x)=x^2$$ with x≥0
Important: Sometimes we must restrict the domain of the original function to make it invertible.
Graphical Relationship: The Line y = x
The graph of f−1 is the reflection of f‘s graph across the line y=x.
Why? Swapping x and y geometrically reflects across y=x.
Example : $$f(x)=2^x$$ and $$f^{-1}(x)=\log_{2}x$$ are reflections across y=x.
Finding Inverses of Non-One-to-One Functions
For functions that fail the horizontal line test, we can restrict the domain to make them invertible.
Example 4: $$f(x)=x^2$$ (not 1-1 over all reals)
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Restrict to x≥0: Inverse is $$f^{-1}(x)=\sqrt{x}$$
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Restrict to x≤0: Inverse is $$f^{-1}(x)=-\sqrt{x}$$
The inverse depends on which branch you choose!