
Understanding rate of change is one of the most important foundations in Precalculus because it leads directly into Calculus, where the derivative measures instantaneous rate of change.
In Precalculus, we focus on average rate of change, interpreting change in graphs, and connecting rate to real-world situations.
Rate of change describes how much one quantity changes in relation to another.
For functions, it measures how much the output (y) changes as the input (x) changes.
General formula:
Rate of change = $$\frac{\Delta{y}}{\Delta{x}}=\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$$
This is called the average rate of change over the interval $$[x_{1} , x_{2}]$$.
For linear functions:
$$f(x)=mx+b$$
The rate of change is constant and equal to the slope mmm.
Positive slope → function increases
Negative slope → function decreases
Zero slope → function is constant
Steeper slope → changes faster
Diagram idea: rising line (positive), falling line (negative), flat line (zero).
Nonlinear functions do not have a constant rate of change.
$$f(x)=x^{2}$$
Compute the rate of change from x=1 to x=3:
$$\frac{f(3)-f(1)}{3-1}=\frac{9-1}{2}=4$$
But from x=3 to x=5:
$$\frac{f(5)-f(3)}{5-3}=\frac{25-9}{2}=8$$
The rate doubled because $$x^{2}$$ gets steeper as x increases.
Key Idea:
For nonlinear functions, the rate of change depends on the interval.
To estimate rate of change:
Choose two points on the graph
Find the rise (change in y)
Find the run (change in x)
Compute slope = rise/run
Upward trend → positive rate
Downward trend → negative rate
Flat segment → rate = 0
This skill is essential for modeling real-world situations.
If distance changes with time:
Rate of change = $$\frac{\Delta{distance}}{\Delta{time}}$$ = average speed
Example:
A car travels from 20 km to 80 km in 1 hour.
average speed = $$\frac{80-20}{1}$$ = 60km/h
If cost changes with production:
$$\frac{\Delta{cost}}{\Delta{items}}$$
Represents marginal cost (approximate rate of cost increase).
$$\frac{\Delta{population}}{\Delta{years}}$$
Measures growth rate over time.
In Precalculus, we compute average rate of change.
But we introduce the idea of instantaneous rate, which is explored fully in Calculus.
$$\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$$
Slope of the tangent line
$$\lim_{\Delta{x}\to{0}}\frac{f(x_{\Delta{x}})-f(x)}{\Delta{x}}$$
Why this matters:
Precalculus prepares you for the idea that slopes of secant lines approximate the slope of the tangent line.
$$f(x)=3x^{2}-2x+1$$
Find rate from x=2 to x=5:
$$\frac{f(5)-f(2)}{5-2}=\frac{66-9}{3}=\frac{57}{3}=19$$
If a population increases from 12,000 to 13,800 in 3 years:
Rate=$$=\frac{13800-12000}{3}=\frac{1800}{3}$$=600people/year
You have not completed all required lessons and assessments.