
Equation: $$x^2+y^2=1$$
For any angle θ in standard position, where the terminal side intersects the unit circle at point (x, y):
$$x=\cos\theta , y=\sin\theta , \tan\theta=\frac{y}{x} (x\neq0)$$
This extends trig functions to ALL angles, not just acute ones!
(0,1)
90° (π/2)
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(√2/2, √2/2) | (√2/2, √2/2)
45° (π/4) | 45° (π/4)
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(-1,0) 180° (π) ---------(0,0)--------- 0° (0) (1,0)
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(√2/2, -√2/2) | (√2/2, -√2/2)
45° (π/4) | 45° (π/4)
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270° (3π/2)
(0,-1)Key Points to Remember:
Quadrant I: (cos θ, sin θ) both positive
Quadrant II: cos negative, sin positive
Quadrant III: both negative
Quadrant IV: cos positive, sin negative
Find reference angle θ’ (acute angle to x-axis)
Determine sign based on quadrant (ASTC)
Use known values for θ’
Apply sign
Example: Find sin 210°
210° is in QIII (180° < 210° < 270°)
Reference angle = 210° – 180° = 30°
sin 30° = 1/2
In QIII, sin is negative
sin 210° = -1/2
$$\sin(\theta+2\pi{n})=\sin\theta , \cos(\theta+2\pi{n})=\cos\theta$$
for any integer n
Period: 2π (360°)
$$\tan(\theta+\pi{n})=\tan\theta$$
for any integer n
Period: π (180°)
Cosine is EVEN: cos(−θ)=cosθ
Sine is ODD: sin(−θ)=−sinθ
Tangent is ODD: tan(−θ)=−tanθ
$$\sin\left(\frac{\pi}{2}-\theta\right)=\cos\theta , \cos\left(\frac{\pi}{2}-\theta\right)=\sin\theta , \tan\left(\frac{\pi}{2}-\theta\right)=\cot\theta$$
Amplitude: 1 (height from midline)
Period: 2π
Domain: All real numbers
Range: [−1,1]
Zeros: x=nπ , n∈Z
Maxima: $$\frac{\pi}{2}+2\pi{n}$$
Minima: $$\frac{3\pi}{2}+2\pi{n}$$
Amplitude: 1
Period: 2π
Domain: All real numbers
Range: [−1,1]
Zeros: $$\frac{\pi}{2}+\pi{n}$$
Maxima: 2πn
Minima: π+2πn
Amplitude: None (unbounded)
Period: π
Domain: $$x\neq\frac{\pi}{2}+\pi{n}$$
Range: All real numbers
Asymptotes: $$x=\frac{\pi}{2}+\pi{n}$$
Zeros: x=πn
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