
In AP Precalculus, zeros of rational functions identify where a function’s output equals zero.
Zeros are closely connected to:
x-intercepts of graphs
Factoring techniques
Domain restrictions
Discontinuities (holes and asymptotes)
Understanding zeros of rational functions requires careful attention to both the numerator and denominator.
A zero of a rational function is a real number xxx such that: f(x)=0
For a rational function:
$$\frac{f(x)}{g(x)}=0 \longrightarrow f(x)=0$$ and $$g(x)\neq0$$
This means:
Zeros come only from the numerator
Denominator values are never allowed
Factor the numerator and denominator completely
Identify values that make the numerator zero
Exclude any values that also make the denominator zero
$$f(x)=\frac{x^2-9}{x-1}$$
Factor numerator:
$$x^2-9=(x+3)(x-3)$$
Zeros:
$$x=\pm3$$
Check denominator:
$$x\neq1$$
Final zeros:
$$x=\pm3$$
$$f(x)=\frac{x^2-4}{x-2}$$
Factor:
$$\frac{(x-2)(x+2)}{x-2}$$
Simplify:
$$f(x)=x+2 , x\neq2$$
x=2 is not a zero
A hole occurs at x=2
Zero:
$$x=-2$$
| Feature | Source | Graph Behavior |
|---|---|---|
| Zero | Uncanceled numerator factor | x-intercept |
| Hole | Canceled factor | Removable discontinuity |
| Vertical asymptote | Denominator factor only | Infinite behavior |
$$f(x)=\frac{x+1}{x-3}$$
Zero at x=−1
Vertical asymptote at x=3
Denominator values are never zeros.
Graph crosses the x-axis
Graph touches the x-axis and turns
Example:
$$f(x)=\frac{(x-2)^2(x+1)}{x-3}$$
Zero at x=2 (even multiplicity)
Zero at x=−1 (odd multiplicity)
To sketch a rational function:
Find zeros (x-intercepts)
Identify holes
Locate vertical asymptotes
Determine end behavior
Zeros anchor the graph to the x-axis.
Zeros of rational functions model:
Break-even points
Equilibrium states
Physical thresholds
Optimization constraints
Zeros occur when the numerator equals zero
Denominator values are excluded
Canceled factors create holes, not zeros
Multiplicity affects graph behavior
Zeros are essential for graphing rational functions
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