AP Course

AP Physics 2

Study AP Physics 2 Units 9–15, with the Fall 2026 radioactive-decay clarification applied and official exam updates linked separately.

Study Units 9–15 through original models, derivations, experiments, quizzes, and practice sets.

Lessons
Particle Motion Behind Temperature and PressureConnecting Gas Variables with the Ideal-Gas ModelHeat Flow and the Approach to Thermal BalanceEnergy Accounting for Thermodynamic ProcessesMaterial Response to Heating and Heat ConductionEntropy, Probability, and the Direction of Thermal ChangeCharge Interactions and Coulomb-Force ModelsTracking Charge During Contact and InductionMapping Electric Fields from Source ChargesEnergy of Configurations of ChargesElectric Potential and Equipotential ReasoningCapacitance and Energy Stored in Electric FieldsConserving Energy in Charged-Particle MotionCharge Flow and Conventional CurrentModeling Sources, Wires, and Loads in Simple NetworksHow Geometry and Material Set ResistanceElectrical Energy Transfer and PowerReducing Series-Parallel DC NetworksLoop Equations from Energy ConservationJunction Equations from Charge ConservationTransient Charging and Discharging in RC NetworksSources, Direction, and Strength of Magnetic FieldsMagnetic Forces and Curved Paths of ChargesForces Between Fields and Current-Carrying ConductorsChanging Magnetic Flux and Induced EMFReflection and Absorption at Material BoundariesLocating Images with Mirror Ray ModelsRefraction, Index, and Total Internal ReflectionLocating Images with Thin-Lens ModelsPulses, Wave Types, and Propagation SpeedPeriodic-Wave Measures and GraphsBoundary Changes and PolarizationElectromagnetic-Wave BehaviorFrequency Shifts from Relative MotionSuperposition, Interference, and Standing WavesDiffraction from Openings and EdgesTwo-Slit and Grating Pattern GeometryPhase Change and Thin-Film ColorQuantum Models and Dual Wave-Particle EvidenceEnergy Levels in a Hydrogen-Like AtomConnecting Spectral Lines to Energy TransitionsThermal Spectra and Blackbody CurvesPhoton Thresholds in the Photoelectric EffectPhoton-Electron Scattering and MomentumMass-Energy Accounting in Fission and FusionRandom Nuclear Decay, Activity, and Half-Life
Quizzes
Practice Problems Formula notes, diagrams, and practice sets will be added here.

AP Physics 2 · Unit 13 · Topic 13.2

Locating Images with Mirror Ray Models

Locate and classify images formed by plane, concave, and convex mirrors. Build the result first with reflected rays, then verify it with the mirror equation and magnification while keeping the sign convention physically meaningful.

Learning Goals

  • Distinguish an object point, an image point, and the path light actually travels.
  • Locate plane-mirror images by backward extension of reflected rays.
  • Use principal rays to construct images for concave and convex spherical mirrors.
  • Apply \(f=R/2\), the mirror equation, and lateral magnification consistently.
  • Interpret signs as real or virtual, upright or inverted, enlarged or reduced.
  • Predict image changes as an object crosses \(C\), \(F\), or moves toward a mirror.
  • Evaluate model limits, experimental evidence, and common ray-diagram errors.
\(d_o\)object distance from mirror vertex
\(d_i\)signed image distance
\(f\)signed focal length
\(m\)signed lateral magnification

1. What Counts as an Image?

An object point sends light along many paths. A mirror redirects part of that light. An image point is the location where reflected rays actually meet or appear to originate.

  • Real image: reflected rays physically pass through the image point. A screen can intercept it.
  • Virtual image: reflected rays diverge, but their backward extensions meet. No light travels through the apparent point, so a screen placed there cannot capture it.

Dashed lines behind a mirror are geometric extensions used by an observer's ray model. They are not additional light rays moving through the mirror.

2. Plane Mirrors: Symmetry Across the Mirror Plane

For every object point, reflected rays reaching an observer behave as if they came from a point equally far behind the mirror. Under the sign convention used in this lesson, a real object has \(d_o>0\) and the plane-mirror image has

\(d_i=-d_o,\qquad m=+1\)

The image is virtual, upright, and the same size as the object. “Left-right reversal” is better understood as front-back reversal: the image is related to the object by reflection across the mirror plane, not by a physical rotation.

Backward extensions locate a plane-mirror imageThe reflected rays remain in front of the mirror. Their dashed extensions meet behind it at a same-size virtual image with \(\lvert d_i\rvert=d_o\).
Worked Example 1 · Plane Mirror

Locate the Image and Object–Image Separation

A student stands \(0.75\,\mathrm m\) in front of a plane mirror.

\(d_i=-d_o=-0.75\,\mathrm m\)
\(\text{object–image separation}=0.75+0.75=1.50\,\mathrm m\)

The image is upright, virtual, and the same size. If the student moves \(0.10\,\mathrm m\) toward the fixed mirror, the image also moves \(0.10\,\mathrm m\) toward it, so their separation decreases by \(0.20\,\mathrm m\).

3. Geometry of Spherical Mirrors

A spherical mirror is part of a sphere. Its vertex \(V\) is where the optical axis meets the surface, its center of curvature \(C\) is the sphere's center, and its radius is \(R=VC\). In the paraxial approximation—rays close to the axis and making small angles—the focal point lies halfway between \(V\) and \(C\):

\(f=\frac{R}{2}\)

A concave mirror is converging and has \(f>0\). A convex mirror is diverging and has \(f<0\). These signs are part of the model, not optional labels added after a calculation.

4. Principal Rays for a Concave Mirror

  1. A ray parallel to the axis reflects through \(F\).
  2. A ray aimed through \(F\) reflects parallel to the axis.
  3. A ray aimed through \(C\) returns along its path because it strikes normally.
  4. A ray striking the vertex reflects with equal angles about the axis.

5. Principal Rays for a Convex Mirror

  1. A parallel ray reflects as if it came from virtual \(F\) behind the mirror.
  2. A ray aimed toward virtual \(F\) reflects parallel to the axis.
  3. A ray aimed toward virtual \(C\) returns along its path.
  4. Extend reflected rays backward with dashed lines to locate the image.

6. A Reliable Ray-Diagram Procedure

  1. Draw the optical axis, mirror vertex, \(F\), and \(C\) to scale when possible.
  2. Draw the object arrow from the axis and begin rays at its tip.
  3. Use any two correct principal rays; the third is a consistency check.
  4. For a real image, mark where reflected rays actually cross.
  5. For a virtual image, extend reflected rays backward with dashed lines.
  6. Draw the image from the axis to the intersection and classify location, orientation, and relative size.

The principal rays are convenient representatives of many rays leaving each object point. Blocking one principal ray does not normally erase a corresponding part of the image.

Concave mirror with \(d_o>f\)A parallel ray reflects through \(F\); a ray through \(F\) reflects parallel. Their physical intersection locates a real inverted image.

7. Mirror Equation and Magnification

For paraxial rays and a spherical mirror, object distance, image distance, and focal length obey

\(\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}\)

The signed lateral magnification connects height and distance:

\(m=\frac{h_i}{h_o}=-\frac{d_i}{d_o}\)

Use the ray diagram to predict the sign and approximate magnitude before calculating. The equation should refine the sketch, not replace physical reasoning.

QuantityPositiveNegative
\(d_o\)real object in front of mirrorvirtual object behind mirror
\(d_i\)real image in front of mirrorvirtual image behind mirror
\(f\) and \(R\)concave mirrorconvex mirror
\(m\) and \(h_i\)upright imageinverted image
Worked Example 2 · Concave Mirror, Object Beyond \(C\)

Find a Reduced Real Image

A concave mirror has \(f=+12\,\mathrm{cm}\). A \(4.0\,\mathrm{cm}\)-tall object is \(36\,\mathrm{cm}\) in front of it.

\(\frac{1}{d_i}=\frac{1}{12}-\frac{1}{36}=\frac{1}{18}\quad\Rightarrow\quad d_i=+18\,\mathrm{cm}\)
\(m=-\frac{18}{36}=-0.50,\qquad h_i=(-0.50)(4.0)=-2.0\,\mathrm{cm}\)

The image lies between \(F=12\,\mathrm{cm}\) and \(C=24\,\mathrm{cm}\), is real, inverted, and half as tall as the object.

Worked Example 3 · Object at the Center of Curvature

Recognize a Symmetric Case

A concave mirror has radius \(R=40\,\mathrm{cm}\), so \(f=20\,\mathrm{cm}\). An object is placed at \(d_o=40\,\mathrm{cm}=2f\).

\(\frac{1}{d_i}=\frac{1}{20}-\frac{1}{40}=\frac{1}{40}\quad\Rightarrow\quad d_i=40\,\mathrm{cm}\)
\(m=-\frac{40}{40}=-1\)

The image is at \(C\), real, inverted, and the same size. This provides a useful calibration point for any concave-mirror ray sketch.

8. Concave-Mirror Image Regimes

Object positionImage positionType and orientationSize
\(d_o>2f\)between \(F\) and \(C\)real, invertedreduced
\(d_o=2f\)at \(C\)real, invertedsame size
\(fbeyond \(C\)real, invertedenlarged
\(d_o=f\)at infinity in ideal modelemerging rays parallelno finite image
\(0behind mirrorvirtual, uprightenlarged
The focal point separates real and virtual regimesFrom \(d_i=fd_o/(d_o-f)\), image distance diverges as \(d_o\to f\). Crossing inside the focus changes the sign of \(d_i\) and makes the image virtual.
Worked Example 4 · Concave Magnifying Mirror

Object Inside the Focal Length

A concave mirror has \(f=+10\,\mathrm{cm}\). An object of height \(1.6\,\mathrm{cm}\) is placed \(6.0\,\mathrm{cm}\) from the mirror.

\(\frac{1}{d_i}=\frac{1}{10}-\frac{1}{6}=-\frac{1}{15}\quad\Rightarrow\quad d_i=-15\,\mathrm{cm}\)
\(m=-\frac{-15}{6.0}=+2.5,\qquad h_i=(2.5)(1.6)=4.0\,\mathrm{cm}\)

The negative image distance places the image behind the mirror; positive magnification makes it upright, and \(\lvert m\rvert>1\) makes it enlarged.

9. What Happens at the Focal Point?

When a real object is at \(d_o=f\), the mirror equation gives \(1/d_i=0\), so the reflected rays are parallel and the ideal image is at infinity. A nearby screen cannot capture a focused image. Moving the object only slightly across \(F\) changes the image from a distant real image to a distant virtual image, so image position is extremely sensitive near the focal point.

This divergence is a model prediction, not an infinite-energy result. Real mirrors have finite aperture, aberrations, and diffraction, and real objects have nonzero depth.

10. Convex Mirrors Always Diverge Reflected Rays

For a real object, a convex mirror has \(f<0\). The reflected rays diverge, and their backward extensions meet behind the mirror between \(V\) and \(F\). Therefore \(d_i<0\), \(m>0\), and \(0

The reduced image allows a wider field of view, which is useful for security and vehicle mirrors. The apparent distance can be misleading because the image is smaller.

A convex mirror has one image regime for real objectsBackward extensions meet behind the mirror between the vertex and virtual focus, so the image is upright, virtual, and reduced at every finite real-object distance.
Worked Example 5 · Convex Security Mirror

Interpret Negative \(f\) and \(d_i\)

A convex mirror has \(f=-20\,\mathrm{cm}\). An object is \(60\,\mathrm{cm}\) in front of it.

\(\frac{1}{d_i}=\frac{1}{-20}-\frac{1}{60}=-\frac{1}{15}\quad\Rightarrow\quad d_i=-15\,\mathrm{cm}\)
\(m=-\frac{-15}{60}=+0.25\)

The virtual image lies \(15\,\mathrm{cm}\) behind the mirror, upright and one quarter the object's height. It lies between the vertex and \(F\), as the ray diagram predicts.

Worked Example 6 · Infer the Mirror Curvature

Work Backward from an Observed Image

A real object is \(30\,\mathrm{cm}\) in front of a mirror. Its upright image is half-size.

\(m=+0.50=-\frac{d_i}{30}\quad\Rightarrow\quad d_i=-15\,\mathrm{cm}\)
\(\frac{1}{f}=\frac{1}{30}+\frac{1}{-15}=-\frac{1}{30}\quad\Rightarrow\quad f=-30\,\mathrm{cm}\)
\(R=2f=-60\,\mathrm{cm}\)

The negative focal length identifies a convex mirror. An upright reduced image for a real object already suggested that classification.

11. Projection Test and the Observer

A real image can be formed on a screen because light from each object point converges to a corresponding image point. A virtual image cannot be projected at its apparent location because the rays do not pass there. Yet an eye or camera can still focus the diverging rays and record a virtual image.

Whether an observer sees an image also depends on whether reflected rays enter the pupil. The geometric image location is set by the mirror and object, not by the observer's position, but the visible portion and field of view can change.

Worked Example 7 · Screen Placement

Decide Whether the Image Is Projectable

A concave mirror has \(f=+15\,\mathrm{cm}\), and an object is \(25\,\mathrm{cm}\) away.

\(\frac{1}{d_i}=\frac{1}{15}-\frac{1}{25}=\frac{2}{75}\quad\Rightarrow\quad d_i=+37.5\,\mathrm{cm}\)
\(m=-\frac{37.5}{25}=-1.50\)

Place the screen \(37.5\,\mathrm{cm}\) in front of the mirror. The image is real, inverted, and enlarged. A screen behind the mirror would not intercept the converging reflected rays.

12. Mirror Power and Curvature

Optical power is the inverse focal length in meters:

\(P=\frac{1}{f}\)

The unit is the diopter, \(\mathrm D=\mathrm{m^{-1}}\). A concave mirror has positive power and a convex mirror has negative power. Greater curvature means smaller \(\lvert R\rvert\), smaller \(\lvert f\rvert\), and larger \(\lvert P\rvert\).

Worked Example 8 · Power and Radius

Convert Between Three Mirror Descriptions

A concave mirror has focal length \(25\,\mathrm{cm}=0.25\,\mathrm m\).

\(P=\frac{1}{0.25}=+4.0\,\mathrm D\)
\(R=2f=+0.50\,\mathrm m\)

A convex mirror with the same curvature magnitude would have \(f=-0.25\,\mathrm m\), \(P=-4.0\,\mathrm D\), and \(R=-0.50\,\mathrm m\).

13. Model Limits and Aberration

The mirror equation assumes a spherical surface and paraxial rays. Rays far from the axis can focus at different locations, producing spherical aberration. A parabolic reflector brings axis-parallel rays to a common focus more accurately.

Off-axis objects can introduce additional aberrations. Ray diagrams remain useful, but their precision must match the approximation.

14. Common Traps

  • Drawing reflected rays through the back of a mirror.
  • Using solid lines for virtual extensions.
  • Assigning \(f>0\) to a convex mirror.
  • Calling every upright image real.
  • Dropping the minus sign in \(m=-d_i/d_o\).
  • Using \(R=f/2\) instead of \(f=R/2\).
  • Starting principal rays from different object points.
  • Trusting algebra without checking the ray-predicted regime.
  • Assuming covering half a mirror removes half the image.

15. Reliable Quantitative Workflow

  1. Classify the mirror and predict the image qualitatively.
  2. Draw a small ray sketch with \(V\), \(F\), \(C\), and the object.
  3. Assign signed \(f\), \(d_o\), and any known \(d_i\) using one convention.
  4. Solve the mirror equation symbolically before substituting values.
  5. Use \(m=-d_i/d_o=h_i/h_o\) for orientation and size.
  6. Translate every sign into words: real or virtual, upright or inverted.
  7. Check the result against the ray regime and limiting behavior.
Mastery Check

1. Reflected rays diverge, but their backward extensions meet behind a mirror. What type of image is present?

Show reasoning and answer

The image is virtual because no reflected light actually travels through the apparent image point.

2. An object is between \(F\) and \(C\) of a concave mirror. Describe the image.

Show reasoning and answer

It forms beyond \(C\), is real, inverted, and enlarged.

3. What image does a convex mirror form for any real object?

Show reasoning and answer

An upright, reduced, virtual image behind the mirror between the vertex and virtual focus.

4. A calculation gives \(d_i=-18\,\mathrm{cm}\) and \(m=+0.60\). Interpret both signs.

Show reasoning and answer

The image is \(18\,\mathrm{cm}\) behind the mirror, so it is virtual. Positive magnification means upright, and \(0.60<1\) means reduced.

5. Why are two principal rays enough to locate an ideal image point?

Show reasoning and answer

Two nonparallel reflected rays or their extensions have a unique intersection. A third ray should pass through the same point and serves as a check.

6. A plane-mirror object approaches the mirror at \(0.40\,\mathrm{m/s}\). How fast does the object–image separation shrink?

Show reasoning and answer

The image approaches the mirror at the same \(0.40\,\mathrm{m/s}\) on the other side, so separation shrinks at \(0.80\,\mathrm{m/s}\).

Investigation: Test Ray Diagrams Against a Mirror Model

Open the PhET Geometric Optics simulation and select the mirror screen. Before moving the object, predict image location, orientation, size, and whether a screen could capture it.

  1. For a concave mirror, place the object beyond \(C\), at \(C\), between \(C\) and \(F\), near \(F\), and inside \(F\).
  2. Record \(d_o\), \(d_i\), and height ratio; test the mirror and magnification equations.
  3. Switch to a convex mirror and verify that the image stays between the vertex and \(F\).
  4. Reduce the mirror aperture. Determine whether image position, size, or brightness changes most.
  5. Estimate uncertainty from reading positions and compare a scale ray drawing with the measured values.

For a real demonstration, use a low-brightness object, concave mirror, and white screen. Never use the Sun or a high-power beam; concentrated light can damage eyes or start a fire.

Official curriculum reference: College Board AP Physics 2 course page. The explanation and worked example are independently written for this study site.