AP Physics 2 · Unit 14 · Topic 14.7
Diffraction from Openings and Edges
Superposition, boundary conditions, diffraction, and phase explain sound and physical-optics patterns.
1. Topic Lens
Diffraction from Openings and Edges is studied through waves, sound, and physical optics. Connect the system boundary, interacting parts, and measurable evidence before applying a formula.
2. Why the Formula Works
The relationship is built from definitions and conservation reasoning:
- A repeating wave advances one wavelength during one period T.
- Speed is distance over time, so v=λ/T.
- Frequency is 1/T, giving v=fλ.
3. Detailed Visual Model
4. Worked Example and Lab Link
A 340 Hz tone travels at 340 m/s. Find its wavelength.
Answer: λ=v/f=1.00 m.
Investigation idea: Measure standing-wave nodes in an air column or string and compare allowed wavelengths with boundary conditions.
Common trap: Wave speed is determined by the medium; changing frequency usually changes wavelength, not the medium's speed.
Expanded Topic 14.7 Lesson
5. Learning Targets
- Explain diffraction at openings and edges using wavefronts and secondary wavelets.
- Predict how the ratio of opening width to wavelength controls angular spreading.
- Derive and apply the single-slit minimum condition.
- Interpret single-slit intensity graphs and calculate the central-maximum width.
- Distinguish near-field, far-field, single-edge, slit, and circular-aperture diffraction models.
6. Diffraction Is Wave Spreading
Diffraction is the redistribution of a wave after it passes through an opening or encounters an obstacle edge. It occurs for mechanical and electromagnetic waves.
- The wave continues into regions that a straight-ray model would label as geometric shadow.
- Different parts of the same wavefront can interfere after the boundary.
- The medium and source frequency need not change.
- Diffraction is strongest and easiest to observe when the relevant opening or obstacle dimension is comparable to the wavelength.
A finite opening always produces some diffraction. When the opening is enormous compared with \(\lambda\), the angular spreading is simply too small to notice easily.
7. Huygens–Fresnel Picture
Treat every unobstructed point on a wavefront as a source of a forward-moving secondary wavelet. The later field is the superposition of those wavelets.
Across a wide opening, most wavelets reinforce straight ahead and only the edges noticeably curve. Across a narrow opening, fewer wavelets span the aperture and the emerging wave spreads over a larger range of directions. Interference between these contributions produces the observed bright and dark structure.
8. Original Opening-Size Model
9. The Dimensionless Control Ratio
This explains why audible sound bends around a doorway more noticeably than visible light: their wavelengths differ enormously while the doorway size is unchanged.
10. Slit Orientation Predicts Spread Direction
Diffraction is controlled by the narrow dimension. A tall vertical slit that is narrow horizontally produces wide horizontal spreading and little vertical spreading. Rotating the slit rotates the diffraction pattern.
This inverse relationship is important: making an aperture narrower in one direction makes its far-field pattern wider in that direction.
11. Deriving Single-Slit Minima
Consider a slit of width \(a\). At observation angle \(\theta\), the path difference between wavelets from the two slit edges is
If \(a\sin\theta=\lambda\), divide the slit into two equal halves. Every point in the upper half can be paired with a point \(a/2\) away in the lower half. Each pair has path difference \(\lambda/2\) and cancels. Extending this pairing gives
These are minimum conditions. \(m=0\) is excluded because \(\theta=0\) is the central maximum.
12. Which Orders Can Exist?
Because \(|\sin\theta|\le1\), a minimum of order \(m\) exists only if
For \(a=2.5\lambda\), minima \(m=\pm1\) and \(m=\pm2\) exist, but \(m=\pm3\) do not. A missing mathematical order is not the same as a detector failing to see a very dim fringe.
13. Original Single-Slit Intensity Graph
14. Intensity Envelope
In the far-field model for a uniformly illuminated slit, define
The angular intensity is
At \(\theta=0\), use the limit \(\sin\beta/\beta\to1\), so \(I=I_0\). The formula assumes coherent monochromatic illumination across the slit and far-field observation.
15. Central-Maximum Width
The first minima occur at \(\sin\theta_1=\lambda/a\). For small angles and a screen distance \(L\), \(y_1\approx L\theta_1\), giving
16. Worked Single-Slit Example
Light of wavelength \(600\,\mathrm{nm}\) passes through a slit of width \(0.120\,\mathrm{mm}\) and reaches a screen \(2.00\,\mathrm m\) away.
The angle is small, so \(\theta_1\approx5.00\times10^{-3}\,\mathrm{rad}\). Therefore
Halving the slit width would double the width of the pattern in this approximation, even though less total light would pass through.
17. Sound Through a Doorway
A \(500\,\mathrm{Hz}\) sound in air at \(343\,\mathrm{m/s}\) has
For a \(0.90\,\mathrm m\)-wide doorway, \(a/\lambda\approx1.31\), so broad spreading is expected. Visible light has wavelength near \(10^{-7}\,\mathrm m\), making the same doorway millions of wavelengths wide and its diffraction angle extremely small.
18. Diffraction at a Single Edge
An opaque straight edge blocks part of a wavefront. Wavelets from the unblocked region extend into the geometric shadow and interfere, producing a softened boundary and, under suitable coherent conditions, alternating bright and dark structure near the edge.
The single-slit condition \(a\sin\theta=m\lambda\) does not apply directly because there is no finite slit width \(a\). Edge diffraction is usually treated with near-field wavefront geometry or Fresnel-zone methods.
19. Near Field and Far Field
The single-slit angular formulas above describe the Fraunhofer regime. A classroom screen at finite distance can approximate it when the geometry and slit size make the far-field condition adequate.
20. Circular Openings and Resolution
A circular aperture produces a central Airy disk surrounded by weaker rings. Its first minimum is approximately
where \(D\) is aperture diameter and \(\theta\) is in radians. The Rayleigh criterion uses this angle as a practical estimate of when two point images are just resolvable.
This is a circular-aperture result; do not replace the slit width \(a\) with \(D\) and keep the single-slit coefficient.
21. Evidence-Building Investigation
- Open PhET Wave Interference and select one opening.
- Hold wavelength fixed while comparing at least three opening widths.
- Measure an angular or screen-width indicator of spreading and graph it against \(1/a\).
- Repeat after changing wavelength and state which dimensionless ratio organizes all trials.
- Sketch the predicted central maximum and first two minima before collecting data.
- Identify the symmetry axis and test whether minima appear in \(\pm m\) pairs.
- Compare the measured central width with \(2L\lambda/a\).
- Discuss slit-width tolerance, screen distance, alignment, finite detector size, and ambient light.
Safety: use only a classroom-approved low-power laser under instructor supervision. Never look into a beam or aim it toward people, reflective surfaces, vehicles, or aircraft.
22. Common Reasoning Traps
- “Diffraction begins only when \(a=\lambda\).” It always occurs; the ratio controls how noticeable the angular spreading is.
- “The wave speed decreases because the wave bends.” Directional redistribution in the same medium does not by itself change speed or frequency.
- Using \(m=0\) as a minimum: the center of a single-slit pattern is bright.
- Confusing slit and double-slit equations: \(a\sin\theta=m\lambda\) identifies single-slit minima.
- Assuming a narrower slit makes a narrower beam: it produces broader angular spreading.
- Applying small-angle formulas at large angles: use \(y=L\tan\theta\) and the exact sine condition when needed.
23. AP-Style Reasoning Checks
- An opening changes from \(10\lambda\) wide to \(2\lambda\) wide. Predict the angular spreading.
- A vertical slit is made narrower horizontally. In which direction does the far-field pattern expand?
- Why is \(m=0\) absent from the single-slit minimum equation?
- If wavelength doubles while \(a\) and \(L\) remain fixed, what happens to the central width?
- Adjacent first minima are \(3.0\,\mathrm{cm}\) apart on a screen \(1.5\,\mathrm m\) away. Estimate \(\lambda/a\).
- Why does increasing telescope diameter improve diffraction-limited resolution?
Answers: it becomes broader; horizontally, perpendicular to the long slit direction; \(\theta=0\) is constructive and forms the central maximum; it doubles in the small-angle model; \(W=2L\lambda/a\) gives \(\lambda/a=0.030/(3.0)=0.010\); a larger aperture decreases the minimum resolvable angle.
Explain how diffraction from openings and edges supports or limits this conclusion: λ=v/f=1.00 m.
Official curriculum reference: College Board AP Physics 2 course page. The explanation and worked example are independently written for this study site.