AP Course

AP Physics C: Electricity and Magnetism

Updated for the AP Physics C: Electricity and Magnetism framework effective fall 2024, with calculus-based fields, circuits, and induction.

Build calculus-based E&M with original field models, derivations, experiments, quizzes, and practice sets.

AP Physics C: Electricity and Magnetism · Unit 8 · Reviewed representative lesson

Gauss’s Law

Gauss's law relates the net electric flux through any closed surface to the net charge enclosed by that surface. It always holds, but it becomes a practical field-solving equation only when symmetry makes the electric-field magnitude and direction simple on the chosen surface.

Definition and Key Formula

\[\oint_S\vec E\cdot d\vec A=\frac{Q_{\mathrm{enc}}}{\varepsilon_0}\]

\(S\) is a closed surface, \(d\vec A\) points outward, \(Q_{\mathrm{enc}}\) is the algebraic sum of charge inside, and \(\varepsilon_0\) is the vacuum permittivity. Charges outside can affect \(\vec E\) locally but contribute zero net enclosed charge.

Choosing a Gaussian Surface

Use a sphere for spherical symmetry, a coaxial cylinder for an effectively infinite line or cylinder, and a pillbox for an effectively infinite plane. The surface is a mathematical construction; it is not a physical membrane that blocks fields.

Worked Example

Question: A point charge \(Q=2.0\,\mathrm{nC}\) is at the center of a spherical Gaussian surface of radius \(0.10\,\mathrm m\). Find the field magnitude on the surface.

\[E(4\pi r^2)=\frac{Q}{\varepsilon_0}\quad\Rightarrow\quad E=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}\]
\[E=(8.99\times10^9)\frac{2.0\times10^{-9}}{(0.10)^2}=1.8\times10^3\,\mathrm{N\,C^{-1}}\]

Answer: The field is \(1.8\times10^3\,\mathrm{N\,C^{-1}}\), directed radially outward.

Why Symmetry Is Essential

Gauss's law gives one scalar flux total. To extract \(E\), symmetry must justify that the field has one magnitude on the relevant surface region and a known angle with \(d\vec A\). Without those facts, the law remains true but does not directly determine the full field.

Common Mistakes

  • Using total charge in the problem instead of enclosed charge.
  • Assuming zero enclosed charge means the electric field is zero everywhere on the surface.
  • Choosing a surface that matches an object's shape but not its charge symmetry.
  • Using an open surface in the closed-surface integral.

Key Takeaways

  • Flux depends on the normal component of the field.
  • Only enclosed charge sets the net closed-surface flux.
  • Symmetry, not visual convenience, determines whether Gauss's law solves \(E\) directly.
Practice connection

Use the quiz and practice tabs to compare spherical, cylindrical, and planar symmetry and to interpret zero-flux cases.

Official curriculum reference: College Board AP Physics C: Electricity and Magnetism course page. The explanation and worked example are independently written for this study site.