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Calculating Equilibrium Concentrations

AP Course

AP Chemistry

Updated for the AP Chemistry framework effective fall 2024, with particle models, quantitative reasoning, labs, quizzes, and practice problems.

Build general chemistry fluency through atomic structure, bonding, reactions, kinetics, equilibrium, acids and bases, thermodynamics, and electrochemistry.

AP Chemistry · Unit 7 · Topic 7.7

Calculating Equilibrium Concentrations

An ICE table is a conservation argument arranged in columns. Its value is not the acronym; it is the way one reaction extent links every concentration change.

Choose a change that has meaning

For \(X_2(g)\rightleftharpoons2X(g)\), let x be the molar concentration of X₂ that dissociates. Then [X₂] falls by x while [X] rises by 2x. The coefficient belongs in the change row as well as in the equilibrium expression. Here the container volume and temperature remain constant.

Organize an original starting mixture

Model dissociation, concentrations in M
StageX₂X
Initial0.1000
Change−x+2x
Equilibrium0.100 − x2x

Because the system begins without X, the initial net direction is forward. Physical limits require \(0\leq x\leq0.100\ \mathrm M\).

Solve rather than guess

At the stated temperature, let \(K_c=0.0400\). Substitution gives

\[0.0400=\frac{(2x)^2}{0.100-x},\qquad4x^2+0.0400x-0.00400=0.\]

The positive root is x = 0.0270 M to three significant figures. Thus [X₂] = 0.0730 M and [X] = 0.0540 M. The negative root would make [X] negative and must be rejected on physical grounds, not just because “we always take plus.”

Perform two independent checks

Substitution gives \(0.0540^2/0.0730\approx0.0400\). Atom conservation gives \(2[X_2]+[X]=0.200\ \mathrm M\), matching the initial total concentration of X atoms. The total concentration of molecules increases, so checking [X₂] + [X] for constancy would be the wrong conservation test.

Test the tempting approximation

If we assumed x was negligible beside 0.100, we would obtain \(x\approx\sqrt{0.0400(0.100)/4}=0.0316\ \mathrm M\). That is 31.6% of the initial concentration, far beyond the common 5% classroom check. The approximation therefore fails. Small K alone is not enough; its size relative to the starting concentration also matters.

Interpret experimental concentration traces

In a suitable spectroscopic model, the X signal should increase while the X₂ signal decreases. Their molar changes must obey the two-to-one relationship after calibration. Raw absorbance changes need not have that ratio because the species may have different molar absorptivities. Check the measurement model before diagnosing a stoichiometric inconsistency.

When the mixture starts with products too

Calculate Q first. If Q exceeds K, choose reverse changes or allow a signed extent and interpret its sign consistently. Do not automatically write every reactant change as negative. The table records what the mixture does, not what the reaction arrow seems to suggest at first glance.

Practice with answers

  1. If x = 0.012 M of X₂ dissociates, how much X appears? 0.024 M.
  2. An approximate x is 0.00080 M from an initial 0.100 M. What is the percentage change? 0.80%, consistent with the usual 5% check.
  3. Why discard a root above 0.100 M here? It would consume more X₂ than was initially available.

Factual reference: OpenStax Chemistry 2e, 13.4. The model reaction, numerical example, evidence discussion, and practice are original.

Official curriculum reference: College Board AP Chemistry course page. The explanation and worked example are independently written for this study site.