AP Biology · Unit 7 · Topic 7.9
Phylogeny
Two species can look alike because they inherited traits from a recent common ancestor, because similar environments favored similar solutions, or simply because the comparison used too little evidence. A phylogeny is a testable hypothesis about branching ancestry that helps distinguish these possibilities. The diagram is not a ladder of progress; its logic lies in the branching pattern.
Read ancestry from nodes, not from the order of the tips
A rooted phylogenetic tree has a direction from an ancestral lineage toward descendants. Each branch represents a lineage, each tip identifies a sampled taxon or lineage, and an internal node represents a hypothesized common ancestor at a divergence. Two lineages that meet at the same immediate node are sister groups.
To compare A with B, trace both branches backward until they first meet. Then do the same for A and C. If the A–B meeting point is more recent than the A–C meeting point, A is more closely related to B. Horizontal distance between printed labels does not answer the question, and counting every node along two paths can fail when one part of the tree contains more sampled lineages.
Branches may be rotated around a node without changing ancestry. Thus (((A,B),(C,D))) and (((B,A),(D,C))) have the same topology. Changing which names appear on the left or top is like turning a mobile; it does not reconnect its pieces.
A clade includes an ancestor and all of its descendants
A clade, or monophyletic group, begins at one node and contains every lineage descending from that node. On a printed tree, a reliable test is to imagine cutting one branch: everything that falls away together forms a clade. Selecting descendants from one node while leaving out another descendant does not produce a complete clade.
A polytomy is a node drawn with more than two descendant branches. It commonly represents unresolved branching order; it does not necessarily assert that all lineages split at exactly the same instant. New evidence can resolve a polytomy, and conflicting evidence can replace one fully resolved tree with another.
No living tip is automatically the ancestor of another living tip. A lineage drawn near the root is not “less evolved,” and a lineage on the far right is not a goal toward which the others progressed. All living lineages have histories extending from their shared ancestors to the present.
Cladograms and scaled trees do not encode the same information
| Representation | What branch order shows | What branch length may show |
|---|---|---|
| Cladogram | Nested relationships and relative branching order | Nothing quantitative unless explicitly stated |
| Phylogram | Nested relationships | Estimated amount of evolutionary change, often substitutions per site |
| Time-calibrated tree | Nested relationships | Elapsed time, using fossil or molecular calibration and a labeled time scale |
| Unrooted tree | Patterns of connection among sampled lineages | Possibly change, if a scale is supplied; not ancestral direction by itself |
“Phylogenetic tree” is a broad term, so never infer time merely because one line is longer. In an unscaled cladogram, a long branch may have been stretched only to fit a label. A time estimate requires a clock model or another calibration, not a ruler placed on an arbitrary drawing.
Build a tree from shared derived characters
A useful character must compare homologous features. An analogous similarity produced independently by convergent evolution can mislead the analysis. An outgroup is a related lineage outside the focal ingroup; comparison with it helps root the tree and infer which state may be ancestral, provided the chosen outgroup and evolutionary assumptions are reasonable.
The following invented matrix uses 0 for the reference state observed in outgroup O and 1 for a derived state. Characters (c_1) through (c_5) are abstract so the exercise tests tree logic rather than memorized anatomy.
| Lineage | (c_1) | (c_2) | (c_3) | (c_4) | (c_5) |
|---|---|---|---|---|---|
| Outgroup O | 0 | 0 | 0 | 0 | 0 |
| A | 1 | 1 | 0 | 0 | 0 |
| B | 1 | 1 | 0 | 1 | 0 |
| C | 1 | 0 | 1 | 0 | 0 |
| D | 1 | 0 | 1 | 0 | 1 |
Character (c_1) supports an ingroup containing A–D. Character (c_2) is a shared derived character supporting the A–B clade, while (c_3) supports the C–D clade. Characters (c_4) and (c_5) distinguish B and D but do not, by themselves, establish a sister pair.
Place character changes on the proposed branches
Under the simplifying assumptions that state 0 is ancestral, each character changes once, and reversals or convergence are absent, this topology requires five changes—one for each character. A topology that separates A from B would require repeated gain or loss of (c_2); separating C from D would do the same for (c_3). Maximum parsimony favors fewer changes, but nature is not required to follow the simplest reconstruction. Likelihood and Bayesian methods can compare models that allow unequal rates, reversals, and repeated changes.
Molecular evidence adds many comparable characters
DNA and protein sequences supply hundreds or thousands of positions that can be compared among lineages. Before counting differences, researchers must identify homologous sequences and align positions that descend from corresponding ancestral positions. A raw similarity score can be misleading if unrelated regions are aligned or if insertions and deletions are handled poorly.
Molecular data often resolve relationships that morphology alone cannot, but a gene tree is not automatically identical to a species tree. Horizontal gene transfer, hybridization, gene duplication, gene loss, and incomplete lineage sorting can give individual genes different histories. Confidence grows when independently informative loci, fossils, and morphology support the same branching pattern.
A tree should therefore be read as a model supported to a stated degree, not as a photograph of the past. New sequences or a better substitution model can revise the topology without making the earlier evidence unscientific.
A molecular clock needs both a rate and a calibration
If substitutions accumulate at an approximately stable rate, sequence divergence can help estimate the time since two lineages separated. Let (d) be corrected pairwise divergence in substitutions per site, (r) the rate in substitutions per site per million years for each lineage, and (t) the time since divergence in million years. With equal rates on the two descendant branches,
\(t=\frac{d}{2r}\)
For an invented example, take (d=0.060) substitutions per site and (r=0.0020) substitutions per site per million years per lineage:
The factor of 2 appears because changes accumulate along both descendant lineages. If a source defines its rate as the combined pairwise divergence rate, the formula would be written differently, so the unit and rate definition must be read first.
This estimate is conditional. It assumes a suitable calibration, approximately clock-like rates, homologous sequence, and correction for substitutions that occurred more than once at the same site. Fossils can provide minimum or maximum constraints, but a fossil's age is not automatically the exact date of the node.
Make only the inference the tree supports
| Claim | Evaluation |
|---|---|
| A and B share a more recent common ancestor with each other than either shares with C. | Supported by the topology. |
| B evolved from A because A is printed above B. | Not supported; both descend from their shared node. |
| C is closer to B on the page, so C and B are closest relatives. | Not supported; tip spacing is arbitrary. |
| A, B, C, and D form a clade relative to O. | Supported by the rooted topology. |
| D experienced the most evolutionary time because its path looks longest. | Not supported; this is an unscaled cladogram. |
The tree does not show which lineage is “best,” whether a trait is beneficial, or how much present-day species resemble their ancestors unless those data are separately encoded. It organizes hypotheses about descent; biological explanations still require the evidence used to build and test it.
Check your tree reasoning
1. Which pairs are sister groups in the invented cladogram?
A and B are sister lineages because their branches meet at the same immediate node. C and D form the other sister pair. The clade A–B is also sister to the clade C–D.
2. If the A and B branches are rotated around their node, does B become more closely related to C?
No. Rotation changes the printed order of tips but preserves every connection. B's most recent common ancestor with A remains more recent than its common ancestor with C.
3. Suppose (c_2) evolved independently in A and B. How would that affect its evidential value?
It would be a homoplasy rather than a single shared derived character inherited from their immediate common ancestor. The character would no longer provide the same support for an A–B clade, so other characters or molecular data would carry more weight.
4. A pairwise divergence is 0.040 substitutions per site and the per-lineage rate is 0.0020 substitutions per site per million years. What is the estimated split time?
Using (t=d/(2r)), (t=0.040/[2(0.0020)]=10) million years. This remains a model-based estimate and needs an appropriate calibration and rate assumptions.
5. Does a three-way polytomy prove that three species originated simultaneously?
No. It usually indicates that the current evidence or analysis does not resolve the branching order. Simultaneous divergence is one possibility, but it is not established by the drawing alone.
6. Why might one gene support a different tree from most of the genome?
The gene may have a different history because of duplication, loss, horizontal transfer, hybridization, or incomplete lineage sorting. Sampling error and model choice are also alternatives. Compare additional independent loci before revising the species-tree hypothesis.
Further reading: OpenStax Biology 2e — Organizing Life on Earth; OpenStax Biology 2e — Determining Evolutionary Relationships; Meir et al. — Understanding Evolutionary Trees through Diagramming Tasks. Scope reference: College Board AP Biology Course and Exam Description, Topic 7.9. Explanations, characters, calculations, questions, tables, and the SVG cladogram were independently written for this lesson; source figures and worksheets are not reproduced.
Official curriculum reference: College Board AP Biology course page. The explanation and worked example are independently written for this study site.
