AP Calculus AB/BC · Unit 10 · Topic 10.1 · BC Only
Defining Convergent and Divergent Infinite Series
Define an infinite series through its partial-sum sequence and distinguish finite accumulation from individual terms.
1. Topic Focus
Determine series convergence, estimate error, construct Taylor approximations, and represent functions with power series on valid intervals.
This topic: Define an infinite series through its partial-sum sequence and distinguish finite accumulation from individual terms.
2. Key Relationship
Read every symbol with its domain, direction, units, and hypotheses before applying the relationship.
3. Visual Connection
4. Worked Example
Convergence asks whether partial sums approach one finite value; small terms alone do not settle that question.
Write the governing relationship first, carry out the algebra cleanly, and finish with a sentence that answers the mathematical question.
5. Concept Development
BC-only topic. An infinite series is not evaluated by completing infinitely many additions. It is defined by a limit of ordinary finite sums. This definition is the foundation for every convergence test in Unit 10.
Sequence terms versus a series
A sequence is an ordered list \(a_1,a_2,a_3,\ldots\). A series is the accumulation of those terms:
The symbol \(n\) is a dummy index. Changing its letter does not change the series, but changing the starting index can add or remove terms.
Partial sums make the definition precise
The \(N\)th partial sum is the finite sum of the first \(N\) terms:
The values \(S_1,S_2,S_3,\ldots\) form a new sequence called the sequence of partial sums. Do not confuse \(a_N\), the newest term, with \(S_N\), the total accumulated through that term.
Definition of convergence
The series converges only when the partial sums approach one finite real number. That limit is called the sum of the series. If the partial-sum limit does not exist as a finite number, the series diverges.
Different ways a series can diverge
- Growth to \(+\infty\): partial sums increase without bound.
- Growth to \(-\infty\): partial sums decrease without bound.
- Oscillation: partial sums alternate between separated values.
- Irregular behavior: partial sums remain unsettled without approaching one limit.
“Diverges” does not mean that every divergent series has sum infinity. Infinity is not a finite series sum.
Recover terms from partial sums
Since consecutive partial sums differ by the newest term,
This relationship allows a problem to specify a series indirectly through a formula, table, or graph for \(S_N\).
A necessary condition for convergence
If \(S_N\to S\), then
Therefore every convergent series must satisfy \(a_N\to0\). The converse is false: terms can approach zero too slowly for their accumulated partial sums to converge. Topic 10.3 develops this divergence test formally.
Telescoping partial sums
Some terms can be rewritten as differences \(a_n=b_n-b_{n+1}\). In a finite partial sum, most intermediate quantities cancel:
The infinite series is then decided by the limit of the remaining boundary expression, not by informal cancellation across an unfinished infinite sum.
Starting index and finite changes
Adding, deleting, or changing finitely many terms changes the numerical sum of a convergent series but does not change whether its tail converges. For an integer \(m>1\),
whenever the original series converges. This principle is useful when reindexing or isolating a tail.
Linearity for convergent series
If \(\sum a_n=A\) and \(\sum b_n=B\) both converge, then for constants \(c,d\),
The convergence assumptions matter. Algebraic combinations of divergent series cannot generally be manipulated as though they had finite sums.
Tables and graphs of partial sums
A table of \(S_N\) suggests convergence when the values settle toward one number, but a finite table alone is not proof. A graph of partial sums should be read as a discrete sequence: convergence means the plotted heights approach one horizontal level as \(N\) grows.
Partial sums as approximations
When a series converges to \(S\), \(S_N\) is a finite approximation and
is the remainder after \(N\) terms. This topic defines the approximation; later topics provide practical error bounds for specific kinds of series.
Definition-first checklist
- Identify the term sequence \(a_n\) and starting index.
- Write or determine the finite partial sum \(S_N\).
- Simplify \(S_N\) before taking a limit.
- Evaluate \(\lim\limits_{N\to\infty}S_N\).
- Conclude “converges to \(S\)” only for a finite limit; otherwise state how it diverges.
- Keep conclusions about \(a_n\) separate from conclusions about \(S_N\).
6. Detailed Worked Example and Error Check
Example 1: Convergence from an explicit partial sum
Suppose \(S_N=N/(N+1)\). Then
Therefore the series converges and its sum is \(1\).
Example 2: Oscillating partial sums
If \(S_N=(-1)^N\), then the even partial sums equal \(1\) and the odd partial sums equal \(-1\). The sequence has no limit, so the series diverges by oscillation.
Example 3: Unbounded partial sums
If \(S_N=\ln(N+1)\), then \(S_N\to+\infty\). The series diverges; it does not have “sum infinity” under the definition of convergence.
Example 4: A basic telescoping series
Use partial fractions:
The finite partial sum is
Thus \(S_N\to1\), so \(\sum_{n=1}^{\infty}1/[n(n+1)]=1\).
Example 5: Two uncanceled terms at each end
For
the partial sum is
Therefore the series converges to \(1/2+1/3=5/6\).
Example 6: Recover the terms from \(S_N\)
Let \(S_N=3-2/N\). The first term is \(a_1=S_1=1\). For \(N\ge2\),
The series sum is \(\lim S_N=3\). The separate formula for \(a_1\) is essential.
Example 7: Remove finitely many terms
Suppose \(\sum_{n=1}^{\infty}a_n=6\), with \(a_1=2\) and \(a_2=-1\). Then
Removing the first two terms changes the sum from \(6\) to \(5\), but the remaining tail still converges.
Example 8: Terms approach zero but the series diverges
For the harmonic series, \(a_n=1/n\to0\). However, grouping terms in partial sums at powers of two gives
These partial sums are unbounded, so \(\sum1/n\) diverges. The condition \(a_n\to0\) was necessary but not sufficient.
Example 9: Terms and partial sums both oscillate
For \(\sum_{n=1}^{\infty}(-1)^n\), the terms alternate between \(-1\) and \(1\), while
The partial sums do not settle, so the series diverges.
Example 10: Infer a partial-sum pattern from a table
Suppose the first partial sums are \(1/2,3/4,7/8,15/16\). The pattern
fits the table and has limit \(1\). If this formula is established for every \(N\), the series converges to \(1\). The table alone only suggests the pattern.
Common errors
- Calling \(a_N\) the partial sum.
- Treating the infinity symbol as a last index that can be substituted.
- Concluding convergence merely because \(a_N\to0\).
- Calling unbounded growth a finite sum.
- Inferring convergence from a short decimal table without a formula or theorem.
- Telescoping an infinite expression without first writing \(S_N\).
- Using \(a_N=S_N-S_{N-1}\) at \(N=1\) without defining \(S_0\).
- Forgetting that removing initial terms changes the sum even though it preserves convergence.
- Combining divergent series through ordinary sum laws.
- Confusing a sequence limit \(\lim a_n\) with the series sum \(\lim S_N\).
7. AP Reasoning Routine
Check the nth-term condition first, match the series structure to a justified test, state convergence type, and test power-series endpoints separately.
- Identify the representation and requested quantity.
- State the rule or theorem and verify its conditions.
- Keep exact values until the final requested approximation.
- Interpret sign, units, interval, and context.
Use the definition through partial sums unless another instruction is given.
(a) For \(a_n=2n-1\), write the first four terms and compute \(S_4\).
(b) A series has \(S_N=(2N+1)/(N+1)\). Determine convergence and its sum.
(c) A series has \(S_N=(-1)^N/N\). Determine convergence and its sum.
(d) A series has \(S_N=\sin(N\pi/2)\). Determine whether it converges or diverges.
(e) A series has \(S_N=\sqrt N\). Describe its divergence.
(f) Evaluate \(\sum_{n=1}^{\infty}1/[n(n+2)]\) by finding a formula for \(S_N\).
(g) If \(S_N=5-3/2^N\), find the series sum, \(a_1\), and a formula for \(a_N\) when \(N\ge2\).
(h) Suppose \(\sum_{n=1}^{\infty}a_n=10\), \(a_1=4\), \(a_2=-2\), and \(a_3=1\). Find \(\sum_{n=4}^{\infty}a_n\).
(i) Explain why \(a_n\to0\) cannot by itself prove that \(\sum a_n\) converges.
(j) If \(S_N=L+(-1)^N/N\), determine the sum of the series.
(k) Given convergent series \(\sum a_n=4\) and \(\sum b_n=-2\), find \(\sum(3a_n-2b_n)\).
(l) The partial sums are \(S_1=0.6,S_2=0.76,S_3=0.824,S_4=0.8496\). Explain what the data can and cannot establish about convergence.
Check the solution
(a) The terms are \(1,3,5,7\), so \(S_4=16\).
(b) \(\lim\limits_{N\to\infty}(2N+1)/(N+1)=2\), so the series converges to \(2\).
(c) Since \((-1)^N/N\to0\), the partial sums converge to \(0\); therefore the series converges and its sum is \(0\).
(d) The partial sums repeat \(1,0,-1,0,\ldots\), so they do not approach one value. The series diverges by oscillation.
(e) Since \(\sqrt N\to+\infty\), the partial sums are unbounded and the series diverges.
(f) Since \(1/[n(n+2)]=\tfrac12(1/n-1/(n+2))\), \(S_N=\tfrac12(1+1/2-1/(N+1)-1/(N+2))\). Hence the sum is \(3/4\).
(g) The sum is \(\lim S_N=5\). Also \(a_1=S_1=7/2\), and for \(N\ge2\), \(a_N=S_N-S_{N-1}=3/2^N\).
(h) The first three terms sum to \(4-2+1=3\), so the tail sum is \(10-3=7\).
(i) Convergence forces terms toward zero, but the converse fails. For example, \(1/n\to0\) while the harmonic partial sums are unbounded.
(j) Because \((-1)^N/N\to0\), \(S_N\to L\). The series converges to \(L\).
(k) Linearity gives \(3(4)-2(-2)=16\).
(l) The values appear to settle and may suggest a limit, but finitely many partial sums cannot prove convergence or identify an exact sum. A formula, bound, or valid convergence theorem is still needed.