AP Calculus AB/BC · Unit 8 · Topic 8.12
Volume with Washer Method: Revolving Around Other Axes
Use distances to a shifted axis for both washer radii.
1. Topic Focus
Apply definite integrals to average value, motion, net change, area, volume, and BC arc length or distance problems.
This topic: Use distances to a shifted axis for both washer radii.
2. Key Relationship
Read every symbol with its domain, direction, units, and hypotheses before applying the relationship.
3. Visual Connection
4. Worked Example
Around y=−1, add 1 to positive y-heights when measuring radii.
Write the governing relationship first, carry out the algebra cleanly, and finish with a sentence that answers the mathematical question.
5. Concept Development
AP focus. The washer formula does not change when the axis moves, but both radii do. For an axis \(y=k\) or \(x=h\), measure perpendicular distances from that line:
The axis shift belongs inside every radius before squaring. Squaring removes a distance's sign; it does not erase the shift.
Horizontal axis \(y=k\)
Use vertical slices and \(dx\). Suppose \(f(x)\ge g(x)\).
- If the axis is below both graphs, \(k\le g(x)\), then \(R=f(x)-k\) and \(r=g(x)-k\).
- If the axis is above both graphs, \(k\ge f(x)\), then the lower graph is farther: \(R=k-g(x)\) and \(r=k-f(x)\).
Vertical axis \(x=h\)
Use horizontal slices and \(dy\), writing the boundaries as \(x=F(y)\) and \(x=G(y)\) with \(F(y)\ge G(y)\).
- If the axis is left of both boundaries, \(h\le G(y)\), then \(R=F(y)-h\) and \(r=G(y)-h\).
- If the axis is right of both boundaries, \(h\ge F(y)\), then \(R=h-G(y)\) and \(r=h-F(y)\).
Check the cross-section type
A washer requires a positive gap between the axis and the entire slice. If the shifted axis lies inside a slice, rotation fills the center and the cross section is a disk with \(r=0\). If the axis enters or leaves the region as the variable changes, split the integral where that happens. Also split wherever the farther boundary changes.
Distance-first workflow
- Draw and label the region and shifted axis.
- Draw a representative slice perpendicular to the axis.
- Measure both endpoint distances from the axis.
- Choose the larger distance as \(R\) and the smaller as \(r\).
- Write \(A=\pi(R^2-r^2)\) with complete parentheses.
- Find bounds and all points where the geometry changes.
- Integrate and report cubic units.
Quick check. Since \(R\ge r\), the integrand \(\pi(R^2-r^2)\) must be nonnegative. A negative expression signals reversed radii or a missing split.
Numerical data. At each listed input, compute the full washer area \(A_i=\pi(R_i^2-r_i^2)\), then approximate \(\int A\). Do not separately average the radii and square them.
6. Detailed Worked Example and Error Check
Example 1: Axis below the region
Revolve the region between \(y=x\) and \(y=x^2\) on \([0,1]\) around \(y=-1\). Since \(x\ge x^2\), the line is farther from the axis:
Example 2: Axis above the same region
Now revolve the same region around \(y=2\). The lower parabola is farther from the axis, so \(R=2-x^2\) and \(r=2-x\):
The same planar region can generate a different volume when the axis moves.
Example 3: Vertical axis left of the region
For \(0\le y\le1\), revolve the region between \(x=y\) and \(x=y^2\) around \(x=-1\). Horizontal slices give
Example 4: Vertical axis right of the region
Revolve that region around \(x=2\). The left boundary \(x=y^2\) is farther from the axis:
Example 5: Constant radii and a geometry check
Revolve the rectangle \(0\le x\le4\), \(1\le y\le3\), around \(y=-2\). The radii are \(R=5\) and \(r=3\):
This agrees with a length-\(4\) outer cylinder of radius \(5\) minus an inner cylinder of radius \(3\).
Example 6: Radius order changes
Rotate the region between \(y=x\) and \(y=1\), \(0\le x\le2\), around \(y=3\). The curves meet at \(x=1\). Before that point \(y=x\) is farther from the axis; afterward \(y=1\) is farther:
Example 7: The shifted axis crosses every slice
Revolve the region between \(y=x^2\) and \(y=2\), \(0\le x\le1\), around \(y=1\). Each vertical slice contains the axis. Rotation fills the center, so these are disks, not washers. The upper endpoint is always distance \(1\), while the lower endpoint is distance \(1-x^2\le1\); therefore
Example 8: Approximate shifted-axis washers from data
At \(x=0,2,4\), suppose \((R,r)=(4,2),(3,1),(2,1)\). The washer areas are \(12\pi,8\pi,3\pi\). The trapezoidal rule gives
Common errors
- Adding or subtracting the shift in only one radius.
- Using the upper graph as \(R\) when the axis is above the region.
- Using the right graph as \(R\) when the axis is to the right of the region.
- Writing \([f(x)]^2-k^2\) instead of \([f(x)-k]^2\).
- Using \(dx\) for washers perpendicular to a vertical axis.
- Failing to split when the radius order or cross-section type changes.
- Using washers when a slice crosses the axis and creates a disk.
- Allowing \(R^2-r^2\) to be negative without correcting the geometry.
7. AP Reasoning Routine
Sketch and label the region, decide whether slices are vertical or horizontal, write a nonnegative geometric quantity, and split bounds when the geometry changes.
- Identify the representation and requested quantity.
- State the rule or theorem and verify its conditions.
- Keep exact values until the final requested approximation.
- Interpret sign, units, interval, and context.
Identify both radii and evaluate each volume unless the prompt asks for classification.
(a) Revolve the region between \(y=3\) and \(y=x\), \(0\le x\le3\), around \(y=-1\).
(b) Revolve the region between \(y=x\) and \(y=x^2\), \(0\le x\le1\), around \(y=-1\).
(c) Revolve the region in part (b) around \(y=2\).
(d) Revolve the region between \(y=4\) and \(y=x^2\), \(-2\le x\le2\), around \(y=-1\).
(e) Revolve the region between \(x=y\) and \(x=y^2\), \(0\le y\le1\), around \(x=-2\).
(f) Revolve the region in part (e) around \(x=3\).
(g) Revolve the rectangle \(0\le x\le5\), \(1\le y\le2\), around \(y=-2\).
(h) Classify and find the volume when the region between \(y=x^2\) and \(y=2\), \(0\le x\le1\), is revolved around \(y=1\).
(i) At \(x=0,1,3\), shifted-axis washer radii are \((R,r)=(4,2),(3,1),(5,4)\). Estimate the volume with the trapezoidal rule.
(j) Explain why both radii must be measured from the shifted axis before either is squared.
Check the solution
(a) The axis is below the region: \(R=4\), \(r=x+1\). Thus \(V=\pi\int_0^3[16-(x+1)^2]dx=27\pi\).
(b) \(R=x+1\), \(r=x^2+1\), so \(V=7\pi/15\).
(c) The axis is above the region: \(R=2-x^2\), \(r=2-x\), so \(V=8\pi/15\).
(d) \(R=5\), \(r=x^2+1\). Therefore \(V=\pi\int_{-2}^{2}[25-(x^2+1)^2]dx=1088\pi/15\).
(e) Use \(dy\). Since the axis is left of the region, \(R=y+2\), \(r=y^2+2\), and \(V=4\pi/5\).
(f) The axis is right of the region, so \(R=3-y^2\), \(r=3-y\), and \(V=13\pi/15\).
(g) \(R=4\), \(r=3\), so \(V=\pi\int_0^5(16-9)dx=35\pi\).
(h) Disks. The axis lies inside every slice, the farther distance is \(1\), and \(V=\pi\int_0^1 1\,dx=\pi\).
(i) The washer areas are \(12\pi,8\pi,9\pi\). Thus \(V\approx1(12\pi+8\pi)/2+2(8\pi+9\pi)/2=27\pi\).
(j) Radius is the perpendicular distance to the actual axis of revolution. The axis shift changes both the outer solid and its central hole, so omitting it from either radius models a different solid.